Page 122 - Advanced Thermodynamics for Engineers, Second Edition
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5.4 EXAMPLES      109




               Q2. Re-evaluate the parameters for the steam plant in Q1 based on t 0 ¼ 81.3 C if (a) The isentropic

                   efficiency of the turbine is 80%; (b) The isentropic efficiency of the feed pump is 70%; (c) If the
                   efficiency of the components is the combination of those given in (a) and (b).
                  Solution
                   (a) Turbine efficiency, h T ¼ 80%.
                  If the turbine efficiency is 80% then the work output of the turbine becomes

                                                  ¼ 0:80   598:2 ¼ 478:6kJ kg:
                                          T
                                    w T ¼ h ðw T Þ isen
                                                            w net  w T þ w P  478:6   2:0
                                                        th                             ¼ 0:194
                  Hence, the thermal efficiency of the cycle is h ¼  ¼    ¼  2799   342:0
                  The rational efficiency is                 q in  h 4   h 2
                                                             478:6   2:0
                                       ½w net Š actual  ½w net Š actual
                                   R
                                  h ¼           ¼         ¼            ¼ 0:798:
                                        b 4   b 2   b w net    597:2
                  The rational efficiency has been significantly reduced by the inefficiency of the turbine, and the
               rational efficiency is approximately equal to the isentropic efficiency of the turbine.
                   (b) Feed pump efficiency, h P ¼ 70%.
                  The feed pump work becomes
                                                       2:0
                                            ðw P Þ isen   ¼ 2:864 kJ=kg:
                                        w P ¼      ¼
                                               h P     0:7
                                    h 0 ¼ h 1 þ dh 12 0 ¼ 340 þ 2:864 ¼ 342:9kJ=kg:
                                     2
                                                            w net  w T þ w P  598:2   2:864
                                                        th
                  The thermal efficiency of the cycle becomes h ¼  ¼      ¼             ¼ 0:242.
                                                            q in  h 4   h 2 0  2799   342:9
                  The exergy at 2 may be evaluated approximately by assuming that the entropy does not change
                               0
               significantly over the pumping process, i.e. s 20 ¼ s 1 :
                  Hence
                         b 2 ¼ h 2   T 0 s 2   a 0 ¼ 342:9   354:3   1:091   a 0 ¼ 43:6   a 0 kJ=kg:
                                      0
                           0
                                0
                  The rational efficiency is
                                                            598:2   2:86
                                           actual     actual
                                       ½w net Š   ½w net Š
                                   R
                                  h ¼          ¼          ¼            ¼ 0:997
                                        b 4   b 2 0  b w net   597:2
                  The reduction in thermal efficiency is small and the rational efficiency is almost 1. Hence, the
               Rankine cycle is not much affected by inefficiencies in the feed pump.
                   (c) Turbine efficiency, h T ¼ 80%; feed pump efficiency, h P ¼ 70%.
                                                            478:6   2:86
                                            w net  w T þ w P
                                        th                             ¼ 0:194
                  The thermal efficiency is h ¼  ¼         ¼
                                             q in  h 4   h 2 0  2799   342:9
                                                                 478:6   2:86
                                            ½w net Š actual  ½w net Š actual
                                        R                                   ¼ 0:797
                  The rational efficiency is h ¼     ¼          ¼
                                             b 4   b 2 0  b w net   597:2
               Q3. Steam turbine cycles
                  The steam plant in question Q2 is modified so that the steam is superheated before entering the
               turbine so that the exit conditions from the turbine of the ideal cycle are dry saturated. Evaluate the
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