Page 220 - Advanced engineering mathematics
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200 CHAPTER 7 Matrices and Linear Systems
First, interchange rows two and three of A to form
⎛ ⎞
−2 1 6 −3
B = ⎝ 0 9 3 −7 ⎠ .
1 1 2 5
Perform this row operation on I 3 to obtain
⎛ ⎞
1 0 0
E 1 = 0 0 1 ⎠ .
⎝
0 1 0
Then
⎛ ⎞⎛ ⎞ ⎛ ⎞
100 −2 1 6 −3 −2 1 6 −3
E 1 A = 001 ⎠⎝ 1 1 2 5 ⎠ = ⎝ 0 9 3 −7 ⎠ = B.
⎝
010 0 9 3 −7 1 1 2 5
Next multiply row three of A by 7 to form
⎛ ⎞
−2 1 6 −3
C = ⎝ 1 1 2 5 ⎠ .
0 63 21 −49
Perform this row operation on I 3 to obtain
⎛ ⎞
1 0 0
E 2 = 0 1 0 ⎠ .
⎝
0 0 7
Then
⎛ ⎞⎛ ⎞ ⎛ ⎞
100 −2 1 6 −3 −2 1 6 −3
E 2 A = 010 ⎠⎝ 1 1 2 5 ⎠ = ⎝ 1 1 2 5 ⎠ = C.
⎝
007 0 9 3 −7 0 63 21 −49
Finally, add 2 times row one to row two to form
⎛ ⎞
−21 6 −3
D = −3 3 14 −1 ⎠ .
⎝
0 9 3 −7
This operation can be achieved by the elementary matrix
⎛ ⎞
1 0 0
E 3 = 2 1 0 ⎠ .
⎝
0 0 1
As a check,
⎛ ⎞⎛ ⎞ ⎛ ⎞
100 −2 1 6 −3 −2 1 6 −3
E 3 A = 210 ⎠⎝ 1 1 2 5 ⎠ = −3 3 14 −1 ⎠ = D.
⎝
⎝
001 0 9 3 −7 0 9 3 −7
This result has an important consequence. Suppose we form B from A by performing a
sequence of elementary row operations in succession. That is, we perform operation O 1 on A to
obtain A 1 , then O 2 on A 1 to form A 2 , and so on until we perform O r on A r−1 to form A r = B.We
may envision this process
O 1 O 2 O 3
A −→ A 1 −→ A 2 −→ A 3 →
O r−1 O r
··· −−→ A r−1 −→ A r = B.
We can perform each elementary operation O j by multiplying on the left by the elementary
matrix E j formed by performing that operation on I n . Then
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October 14, 2010 14:23 THM/NEIL Page-200 27410_07_ch07_p187-246