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7.1 Matrices 197
Suppose we want the number of walks of length 3 in this graph. Calculate
⎛ ⎞
0 5 1 4 2 4 3 2
⎜ 6 2 7 4 5 4 9 8 ⎟
⎜ ⎟
⎜ 1 7 0 8 3 2 3 2 ⎟
⎜ ⎟
4 4 8 6 8 8 11 10 ⎟
3
⎜
A = ⎜ ⎟ .
⎜ 2 5 3 8 4 6 8 4 ⎟
⎜ ⎟
⎜ 4 4 2 8 6 2 4 4 ⎟
⎜ ⎟
⎝ 3931184 6 7 ⎠
2821044 7 4
3
For example, the 4,7 element of A is 11, so there are 11 walks of length 3 between v 4 and v 7 .
There are no walks of length 3 between v 4 and v 6 .
Generally we would use a software package to compute A .
k
SECTION 7.1 PROBLEMS
In each of Problems 1 through 6, perform the requested −2 −4 6 8
8. A = ,B =
computation. 3 −1 1 −4
⎛ ⎞ ⎛ ⎞
1 −1 3 −4 0 0 ⎛ −3 ⎞
1. A= ⎝ 2 −4 6 ⎠ ,B= ⎝ −2 −1 6 ⎠ ;2A−3B
⎜ 2 ⎟
−1 1 2 8 15 4 9. A = −1 6 2 14 −22 ,B = ⎜ 6 ⎟
⎟
⎜
⎜ ⎟
⎝ 0 ⎠
⎛ ⎞ ⎛ ⎞
−2 2 4 4 −4
0 1 2 1
⎜ ⎟ ⎜ ⎟
2. A = ⎜ ⎟ ,B = ⎜ ⎟ ,−5A + 3B
⎝ 14 ⎝ 14
2 ⎠ 16 ⎠ ⎛ −3 1 ⎞
6 8 1 25
6 2 −16 0 0 28
⎜ ⎟
10. A = ⎜ ⎟ ,B =
⎝ 18 0 1 1 26
x 1 − x 1 −6
−22 ⎠
2
3. A = x ,B = ,A + 2AB 1 6
2 e x cos(x)
⎛ ⎞
4. A = (14),B = (−12),−3A − 5B −21 4 8 −3
⎜ 12 1 0 14 ⎟
1 −2 1 7 −9 11. A = ⎜ ⎟ ,
5. A = , ⎝ 1 16 0
8 2 −5 0 0 −8 ⎠
13 4 8 0
−5 1 8 21 7
B = ,4A + 8B
12 −6 −2 −1 9 −9 16 3 2
B =
5 9 14 0
−2 3 0 8
3
6. A = ,B = ,A − B 2
1 1 −5 1 −2 4 1 −3 7 2
12. A = ,B =
3 9 5 9 1 0
In each of Problems 7 through 16, determine which of AB
and BA are defined. Carry out all such products. ⎛ ⎞
−4 −2 0
⎛ ⎞ 13. A = ⎝ 0 5 3 ⎠ ,B = 1 −3 4
−4 6 2
7. A = ⎝ −2 −2 3 ⎠ , −3 1 1
1 1 8
3
⎛ ⎞
−2 4 6 12 5
⎛ ⎞
⎜ 0 ⎟
B = ⎝ −3 −3 1 1 4 ⎠ 14. A = ⎜ ⎟ ,B = 3 −2 4
⎝ −1 ⎠
0 0 1 6 −9
4
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October 14, 2010 14:23 THM/NEIL Page-197 27410_07_ch07_p187-246