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320    CHAPTER 10  Systems of Linear Differential Equations

                                 The system of two second-order equations translates to the following system in terms of
                                 x 1 ,··· , x 4 :


                                                        x = y = x 3 ,
                                                         1   1

                                                        x = y = x 4 ,

                                                             2
                                                         2

                                                        x = y =−8y 1 + 2y 2 =−8x 1 + 2x 2 ,

                                                             1
                                                         3

                                                        x = y = 2y 1 − 5y 2 = 2x 1 − 5x 2 ,

                                                         4
                                                             2
                                 and
                                                       x 1 (0) = 1, x 2 (0) =−1, x 3 (0) = x 4 (0) = 0.
                                 This is the system X = AX with

                                                                 ⎛             ⎞
                                                                   0   0   1 0
                                                                   0   0   0 1
                                                                 ⎜             ⎟
                                                             A =  ⎜            ⎟
                                                                 ⎝ −8  2   0 0 ⎠
                                                                   2   −5  0  0
                                 and
                                                                       ⎛   ⎞
                                                                         1
                                                                        −1
                                                                       ⎜   ⎟
                                                                X(0) =  ⎜  ⎟ .
                                                                       ⎝ 0 ⎠
                                                                         0
                                 A has the characteristic equation
                                                                 2
                                                                       2
                                                               (λ + 4)(λ + 9) = 0
                                 with eigenvalues ±2i and ±3i. Corresponding to the eigenvalues 2i and 3i, we find two
                                 eigenvectors
                                                       ⎛ ⎞    ⎛ ⎞      ⎛   ⎞    ⎛   ⎞
                                                         1      0        2        0
                                                         2      0        −1       0
                                                       ⎜ ⎟    ⎜ ⎟      ⎜   ⎟    ⎜   ⎟
                                                            + i    and       + i      .
                                                       ⎜ ⎟    ⎜ ⎟      ⎜   ⎟    ⎜   ⎟
                                                       ⎝ 0 ⎠  ⎝ 2 ⎠    ⎝ 0 ⎠    ⎝ 6 ⎠
                                                         0      4        0        −3
                                 The complex conjugates of these eigenvectors are also eigenvectors corresponding to eigenvalues
                                 −2i and −3i. However, we will not write these other two eigenvectors, because we will use The-
                                 orem 10.8 to write the four linearly independent solutions involving only real-valued functions.
                                 From the eigenvector for 2i, write the two solutions
                                            ⎛ ⎞          ⎛ ⎞              ⎛ ⎞         ⎛ ⎞
                                              1            0                1           0
                                                                            2
                                                                                        0
                                                           0
                                              2
                                            ⎜ ⎟          ⎜ ⎟              ⎜ ⎟         ⎜ ⎟
                                            ⎜ ⎟  cos(2t) −  ⎜ ⎟ sin(2t)  and  ⎜ ⎟ sin(2t) +  ⎜ ⎟ cos(2t).
                                            ⎝ 0 ⎠        ⎝ 2 ⎠            ⎝ 0 ⎠       ⎝ 2 ⎠
                                              0            4                0           4
                                 From the eigenvector for 3i, write the two solutions
                                         ⎛   ⎞         ⎛    ⎞             ⎛   ⎞         ⎛   ⎞
                                            2             0                 2             0
                                         ⎜ −1 ⎟        ⎜  0  ⎟            ⎜ −1 ⎟        ⎜  0  ⎟
                                         ⎜   ⎟  cos(3t) −  ⎜  ⎟ sin(3t)  and  ⎜  ⎟  sin(3t) +  ⎜  ⎟  cos(3t).
                                         ⎝ 0 ⎠         ⎝ 6 ⎠              ⎝ 0 ⎠         ⎝ 6 ⎠
                                            0            −3                 0            −3
                                 Use these four linearly independent solutions as columns of the fundamental matrix
                                                     ⎛                                       ⎞
                                                       cos(2t)   sin(2t)  2cos(3t)   2sin(3t)
                                                     ⎜  2cos(2t)  2sin(2t)  −cos(3t)  −sin(3t)  ⎟
                                               (t) =  ⎜                                      ⎟ .
                                                     ⎝ −2sin(2t)  2cos(2t) −6sin(3t)  6cos(3t) ⎠
                                                      −4sin(2t)  4cos(2t)  3sin(3t)  −3cos(3t)
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                                   October 14, 2010  20:32  THM/NEIL   Page-320        27410_10_ch10_p295-342
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