Page 129 - Advanced thermodynamics for engineers
P. 129

5.4 EXAMPLES      115




                  Temperature after compressor, at 2 is
                                               w C       ð 509:9Þ
                                      T 2 ¼ T 1    ¼ 300         ¼ 807:6K
                                               c p        1:0045
                  The energy added to the cycle is

                              q 23 ¼ c p T 3   T 2 ¼ 1:0045   1200   807:6 ¼ 394:2kJ kg:
                  The net work from the cycle is w net ¼ w T þ w C ¼ 693.2 þ ( 509.9) ¼ 183.3 kJ/kg and the thermal
                               w net  183:3
               efficiency is h ¼    ¼      ¼ 0:465:
                           th
                               q 23  394:2
                  The maximum net work output is defined by
                                                  b w net ¼ b 3   b 2 :

                  Since both 2 and 3 are at the same pressure

                                                                    T 3
                                         b 3   b 2 ¼ c p ðT 3   T 2 Þ  T 0 ln
                                                                    T 2
                  Thus

                                                                1200
                             b w net ¼ 1:0045   ð1200   807:6Þ  300 ln  ¼ 273:6kJ=kg:
                                                                807:6
                  The rational efficiency of the cycle based on these dead-state conditions is
                                                 w net  183:3
                                            h ¼      ¼      ¼ 0:670:
                                             R
                                                  b w net  273:6
                  The net work output of the device is made up of


                       w net ¼ b w net  ½ b w net Š rejected    T 0 s 2   s 2s ¼ 273:6   50:9   40:2 ¼ 182:5kJ=kg:
                  In this case, the inefficiency of the compressor has introduced a quantity of unavailable energy
               T 0 (s 2   s 2s ), which is depicted on Fig 5.7.
                   (c) Compressor isentropic efficiency, h C ¼ 80% and turbine isentropic efficiency, h T ¼ 80%.
                  Thiscyclecombinesthetwoinefficienciesconsideredabove.Hence,thenetworkoutputofthecycleis

                                   w net ¼ w T þ w C ¼ 554:6 þð 509:9Þ¼ 44:7kJ=kg:
                  Net heat addition q 23 ¼ 394.2 kJ/kg.
                  Hence, thermal efficiency is

                                                 w net  44:7
                                            h ¼      ¼      ¼ 0:113:
                                              th
                                                  q 23  394:2
                  The net work output of this cycle is made up in the following way

                                 w net ¼ b w net  ½ b w net Š rejected    T 0 s 4   s 4s   T 0 s 2   s 2s
                                     ¼ 273:6   117:4   72:2   40:2 ¼ 43:8kJ=kg
   124   125   126   127   128   129   130   131   132   133   134