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5. The PV Arrays     37


















                  FIGURE 1.32
                  Equivalent circuit of the module.

                     Because the cells are identical, they have the same output voltage V c , and
                  because they are connected in series, they have the same terminal current I st .As
                              V c ¼ V j þ I st R s ; V j ¼ V c   I st R s ; and I st ¼ I ph   I d ;

                  it follows that
                                                             !
                                                     ðVc þI st Rs Þ
                                        I st ¼ I ph   I s e  nV T    1          (1.49)

                  The overall module voltage is the sum of cell voltages in the module
                                                 n e
                                                X
                                           V m ¼   V c ¼ n e V c                (1.50)
                                                 1
                  Substituting Eq. (1.50) in (1.49), we get the IeV of the string
                                                              !
                                                    ðV m =n e þI st R s Þ
                                       I st ¼ I ph   I s e  nV T    1           (1.51)

                     This equation is very simple. To pass the same current in the string, the string
                  voltage must be exactly a multiple of n e of the cell voltage.
                     Now let us pay our attention to the parallel connection of n s strings. Because all
                  cells are identical, the string current is the same in each string while the string volt-
                  ages are the same, i.e., V m . Hence,

                                                 n s
                                                X
                                           I m ¼   I st ¼ n s I st              (1.52)
                                                 1
                     The IeV characteristics of the module can be obtained by substituting Eq. (1.52)
                  in (1.51), i.e.,
                                                                !
                                                     ðVm =ne þI st Rs Þ
                                     I m ¼ n s I ph   n s I s e  nV T    1      (1.53)
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