Page 43 - Aerodynamics for Engineering Students
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26  Aerodynamics for Engineering Students
                giving

                                p = 1.71 x  1.0246 x   = 1.751 x  lop5 kgm-’s-l
                For dynamic similarity the Reynolds numbers must be equal, Le.

                                          287 x  1 x p  = 20.2 x  106
                                          1.75 x  10-5
                giving

                                                  p = 1.23kgmP3
                Thus the static pressure required in the test section is
                                  p  = pRT  = 1.23 x 287.3 x 282 = 99500Nm-*
                The total pressure ps is given by

                                    e= +tM2)3’5= (1.1445)3.5 = 1.605
                                        (1
                                    P
                                    ps = 99 500 x  1.605 = 160 000 N mP2
                If the total pressure available in the tunnel is less than this value, it is not possible to achieve
                equality of both the Mach and Reynolds numbers. Either the Mach number may be achieved
                at a lower value of Re or, alternatively, Re may be made equal at a lower Mach number. In
                such a case it is normally preferable to make the Mach number  correct  since, provided  the
                Reynolds number in the tunnel is not too low, the effects of compressibility are more important
                than the effects of aerodynamic scale at Mach numbers of this order. Moreover, techniques are
                available which can alleviate the errors due to unequal aerodynamic scales.
                  In particular,  the  position  at which  laminar-turbulent  transition  (see  Section 7.9)  of  the
                boundary layer occurs at full scale can be fixed on the model by roughening the model surface.
                This can be done by gluing on a line of carborundum powder.

                  1.5  Basic aerodynamics

                1.5.1  Aerodynamic force and moment

                Air flowing past an aeroplane, or any other body, must be diverted from its original
                path, and such deflections lead to changes in the speed of the air. Bernoulli’s equation
                shows that the pressure exerted by the air on the aeroplane is altered from that of the
                undisturbed  stream. Also the viscosity of  the air leads to the existence of  frictional
                forces tending to resist its flow. As a result of these processes, the aeroplane experiences
                a resultant  aerodynamic  force and  moment.  It is  conventional  and  convenient to
                separate this aerodynamic force and moment into three components each, as follows.

                Lift, LI-Z)
                This is  the  component  of  force acting upwards,  perpendicular  to the  direction  of
                flight or of the undisturbed stream. The word ‘upwards’ is used in the same sense that
                the  pilot’s  head  is  above  his  feet.  Figure  1.7  illustrates  the  meaning  in  various
                attitudes  of  flight.  The  arrow  V  represents  the  direction  of  flight,  the  arrow  L
                represents the lift acting upwards and the arrow  W the weight of  the aircraft, and
                shows the downward vertical. Comparison of (a) and (c) shows that this upwards is
                not fixed relative to the aircraft, while (a), (b), and (d) show that the meaning is not
                fixed relative to the earth. As a general rule, if it is remembered that the lift is always
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