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38                                            2  Basic Properties of Gases

            Solution
            Step 1. Determine the molar weight of the gases

            Gas or Vapor                   Molar weight (g/mol)
            H 2                             2
            H 2 O                          18
            Air                            29
            CO 2                           44
            Step 2. Compute the root-mean-square speed of the gas molecules using Eq. (2.45)
            and the kinetic energy of 1 mol of the gas using Eq. (2.46)

            Gas or Vapor  Molecular weight (g/mol)  Equation (2.45)  Equation (2.46) (J/mol)
                                              c rms (m/s)
            H 2           2                   1911.54       3654.0
            H 2 O        18                    637.18       3654.0
            Air          29                    501.99       3654.0
            CO 2         44                    407.54       3654.0
              It is apparent that the lighter molecules have the greater root-mean-square speeds
            to maintain the equal kinetic energy at the same temperature.


            2.1.7 Gas Mean Free Path


            The mean free path of a gas is the average distance traveled by gas molecule
            between the collisions. Gas mean free path affects the aerosol dynamics and con-
            sequently air sampling and cleaning technologies. Gas mean free path may be
            estimated from kinetic theory too.
              Consider a gas with molecules with a uniform diameter of d. As shown in
            Fig. 2.2, the effective cross section for collision is d c ¼ 2d, and the cross section
                                        2
            area can be calculated as A ¼ 4pd .


            Fig. 2.2 Collision diameter
            of gas molecules
                                                       Miss



                                       d

                                                                Collide
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