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42                                            2  Basic Properties of Gases

              Substitute Eq. (2.7) into this equation and we can get

                                              r ffiffiffiffiffiffiffiffiffi
                                                kT
                                       J x ¼ C N                         ð2:60Þ
                                                2pm
              Considering the relationship between gas density and the molecule number
            concentration described in Eq. (2.50), the total number of collisions per unit time
            per unit area can also be expressed in terms of gas density as
                                            r ffiffiffiffiffiffiffiffiffiffiffi
                                               kT
                                       J x ¼ q    :                      ð2:61Þ
                                              2pm 2
            2.1.9 Diffusivity of Gases


            We can derive the diffusivity of a single gas by applying the preceding analysis of
            molecule collision on a surface to an imaginary cubic container that is formed by a
            distance of mean free path, 2k. We can apply finite element analysis from x   kÞ to
                                                                      ð
            ð x þ kÞ. The concentration at x is C N . Assuming a constant gas concentration
            gradient of  dC N  from x   kÞ to x þ kÞ; the concentrations at x þ kÞ and x   kÞ
                                     ð
                             ð
                                                                        ð
                                                              ð
                      dx

                     dC N           dC N
            are C N þ   k and C N      k , respectively.
                     dx              dx
              Considerations of symmetry lead us to assert that the average number of particles
            traveling in a given direction ð x;  y or   zÞ will be one-sixth of the total, and
            thus the mean rate at which molecules crosses a plane is N  c=6 per unit area in unit
            time. N is the total number of molecules in the container. This differs slightly from
            the exact result, although it is suitable for some simplified argument.
              Statistically, 1/6 of the molecules at x þ kÞ will move along  x direction.
                                              ð
            According to the definition of mean free path, these molecules leaving the plane
            ð x þ kÞ along  x direction will reach plane x. Therefore, the number of molecules
            leaving plane x þ kÞ per second per unit area is
                       ð
                                        1       dC N
                                   J  x ¼  C N þ    k   c
                                        6        dx
              Similarly, the number of molecules per second per unit area leaving plane
            ð x   kÞ to plane x is

                                        1       dC N
                                   J !x ¼  C N      k   c
                                        6        dx
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