Page 501 - Air and Gas Drilling Manual
P. 501

10-26    Air and Gas Drilling Manual
                                            .
                                           0 00015 ft
                                      e
                                       p
                               Using Equation 106, the Fanning friction factor,  f , for flow inside  the return flow
                                                                    sr
                               line is
                                                                 2
                                                      1
                                      f sr         0 469
                                                    .
                                            2 log            114
                                                              .
                                                    .
                                                   0 00015
                                            .
                                      f sr  0 015
                                   Equation 10-4 for the surface return flow line increment can be  solved  for  the
                               pressure at the entrance end of the line,  P .  This involves selecting this upper limit
                                                             sr
                               of the left side integral by a trial and error procedure.   The magnitude of the upper
                               limit  pressure  on  the  left  side  of  the  equation  is  selected  to  allow  the  left  side
                               integral to  equal the right side integral.   The integration can be carried  out  on  the
                               computer using one of the commercial analytic software programs (e.g.,  MathCad).
                               The trial and error magnitude of the upper limit pressure is
                                              .
                                      p sr  31 98 psia
                                      P     p 144
                                       sr    sr
                                                     2
                                             ,
                                                .
                                      P sr  4 604 4 lb/ft abs
                                   Substituting the values of  L ,  ˙ w , Q g, Q m, P g, P bp,  P ,  T g, T r,  D ,  f ,  and
                                                       sr
                                                           t
                                                                                        sr
                                                                                    sr
                                                                           sr
                               g into the left side of Equation 10-4 gives
                                       ,
                                     ∃  4 604 4 .
                                     &
                                     &                       dP
                                     &                                          2    100
                                                                   ,
                                     &                            49 004 7 .     !
                                                                            .
                                     &          17 37       0 015   P      0 234
                                                             .
                                                  .
                                     % 4 274 6 .  49 004 7 .                     ∀
                                      ,
                                              ,
                                                              .
                                                     0 234  30 20     (.   2
                                                                       0 469)
                                                      .
                                               P                     4
                                                                                 #
                               Substituting the value of  L  into the right side of Equation 10-4 gives
                                                   sr
                                       100
                                          1 dh  100
                                       0
   496   497   498   499   500   501   502   503   504   505   506