Page 264 - Aircraft Stuctures for Engineering Student
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8.4  Symmetric manoeuvre loads  245

                 The loads are in static equilibrium since the aircraft is in a steady, unaccelerated,
               level fight condition. Thus for vertical equilibrium
                                            L+P-  w=o                              (8.7)

               for horizontal equilibrium
                                              T-D=O
               and taking moments about the aircraft’s centre of gravity in the plane of symmetry

                                      La - Db - Tc - Mo -PI  = 0                   (8.9)
               For a given aircraft weight, speed and altitude, Eqs (8.7), (8.8) and (8.9) may be solved
               for  the  unknown  lift,  drag  and  tail  loads.  However,  other  parameters  in  these
               equations, such as Mo, depend upon the wing incidence a which in turn is a function
               of the required wing lift so that, in practice, a method of successive approximation is
               found to be the most convenient means of solution.
                 As a first approximation we assume that the tail load P is small compared with the
               wing lift L so that, from Eq. (8.7), L M W. From aerodynamic theory with the usual
               notation



               Hence
                                             +pv2sc, M w                          (8.10)

               Equation  (8.10) gives the  approximate lift coefficient  CL and thus  (from CL - a
               curves established by wind tunnel tests) the wing incidence a. The drag load D follows
               (knowing V and a) and hence we obtain the required engine thrust T from Eq. (8.8).
               Also Mo, a, b, c and I may be calculated (again since V and a are known) and Eq. (8.9)
               solved for P. As a second approximation this value of P is substituted in Eq. (8.7) to
               obtain a  more accurate value for L  and the procedure is  repeated. Usually three
               approximations are sufficient to produce reasonably accurate values.
                 In most cases P, D  and  T are small compared with the lift and aircraft weight.
               Therefore, from Eq. (8.7) L M W and substitution in Eq. (8.9) gives, neglecting D
               and T

                                                                                  (8.11)

                 We see from Eq. (8.1 1) that if a is large then P will most likely be positive. In other
               words the tail load acts upwards when the centre of gravity of the aircraft is far aft.
               When a is small or negative, that is, a forward centre of gravity, then P will probably
               be negative and act downwards.



               8.4.2  General case of a symmetric manoeuvre
               l*-llll_-----s._~_-~                 _YI         ._I_Y_-_..-_-*I,_I_Y_LIY.I-Ylli
               In a rapid pull-out from a dive a downward load is applied to the tailplane, causing the
               aircraft  to  pitch  nose  upwards.  The  downward load  is  achieved  by  a  backward
               movement of the control column, thereby applying negative incidence to the elevators,
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