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9.4 Shear of closed section beams  301


















              Fig. 9.23  Shear of closed section beams.
              Let us suppose that we choose an origin for s where the shear flow has the unknown
              value qs,o. Integration of Eq. (9.33) then gives




              or




              We  observe by comparison of  Eqs (9.35) and (9.34) that the first two terms on the
              right-hand side of Eq. (9.35) represent the shear flow distribution in an open section
              beam loaded through its shear centre. This fact indicates a method of solution for a
              shear loaded closed section beam. Representing this 'open'  section or 'basic'  shear
              Aow by qb, we may write Eq. (9.35) in the form

                                             4.7  = qb + qs,O                    (9.36)
              We obtain qb by supposing that the closed beam section is 'cut'  at some convenient
              point  thereby  producing  an  'open'  section  (see  Fig.  9.24(b)).  The  shear  flow






















              Fig. 9.24  (a) Determination of q,,o; (b) equivalent loading on 'open'section  beam.
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