Page 549 - Aircraft Stuctures for Engineering Student
        P. 549
     530  Matrix methods of  structural analysis
                  which is of the form
                                                (0 = [Al{a>
                  Then
                                                                                   ( 12.100)
                  The inversion of [A] is illustrated in Example 12.4 but, as in the case of the triangular
                  element, is most easily carried out by means of a computer. The remaining analysis
                  is identical to that for the triangular element except that the {E} - {a} relationship
                  (see Eq. (12.89)) becomes
                                         [:     o  y  o  o 0
                                   {E}=   0     0000 1                             (12.101)
                                                 1x01 0
                  Example 12.4
                  A rectangular element used in a plane stress analysis has corners whose coordinates
                  (in metres), referred to an  Oxy axes  system, are  1(-2,  -l),  2(2, -l),  3(2,1) and
                  4(-2,l);  the displacements (also in metres) of the corners were
                              ~1  = 0.001,   ~2  = 0.003,   ~3  = -0.003,   ~4 = 0
                              211  = -0.004,   212  = -0.002,   213  = 0.001,   214  = 0.001
                  If Young's modulus E = 200000N/mm2 and Poisson's ratio v = 0.3, calculate the
                  stresses at the centre of the element.
                    From the first of Eqs (12.96)
                                       u1  =a1 - 2a2 - a3 + 2a4 = 0.001
                                       u2 = a1 + 2a2 - a3 - 2a4 = 0.003
                                       u3 = a1 + 2a2 + a3 + 2a4 = -0.003
                                       U4  =a1 -2a2  +a3 -2a4  = 0
                  Subtracting Eq. (ii) from Eq. (i)
                                               a2 - a4 = 0.0005
                  Now subtracting Eq. (iv) from Eq. (iii)
                                              CY^ + a4 = -0.00075
                  Then subtracting Eq. (vi) from Eq. (v)
                                               a4 = -0.000625                          (vii)





