Page 591 - Aircraft Stuctures for Engineering Student
        P. 591
     572  Elementary aeroelasticity
                 unit displacement (kd) is equal to the force produced by the unit rotation (kd). Also, if
                 the arbitrarily chosen point 0 is made to coincide with the flexural axis, d = 0 and the
                 coupling disappears.
                   From the above it can be seen that flutter will be prevented by uncoupling the two
                 constituent motions.  Thus, inertial coupling is prevented if  the  centre of  gravity
                 coincides with the flexural axis, while aerodynamic coupling is eliminated when the
                 centre of  independence coincides with the flexural axis. This, in  fact, would also
                 eliminate elastic coupling since 0 in  Fig.  13.22 would generally be  the centre of
                 independence. Unfortunately, in practical situations, the centre of independence is
                 usually forward of the flexural axis, while the centre of gravity is behind it giving
                 conditions which promote flutter.
                 13.4.2  Determination of critical flutter speed
                 Consider a wing section of chord c oscillating harmonically in an airflow of velocity V
                 and density p and having instantaneous displacements, velocities and accelerations of,
                 rotationally, a, d!, &, and, translationally, y, j, 9. The oscillation causes a reduction in
                 lift from the steady state lift4 so that, in effect, the lift due to the oscillation acts
                 downwards. The downward lift corresponding to a, d!  and & is, respectively
                                               1,pcv2a = L,a
                                               lbPC2Vd!  = L&&
                                                I..  c3& = L&&
                                                 CYP
                 in which I,,  I&, lii! are non-dimensional coefficients analogous to the lift-curve slopes in
                 steady motion. Similarly, downward forces due to the translation of the wing section
                  occur and are
                                              IypcV2y/c = Lyy
                                              Ijpc2vj/c  = Lyj
                                                I..  c3 " c - L  *-
                                                yP  Yl  - yY
                  Thus, the total aerodynamic lift on the wing section due to the oscillating motion is
                  given by
                                   L = Lyy + LyJj + Lyy + L,a + L&d! + L&&          (1 3.60)
                  We  have previously seen  that  rotational  and translational  displacements produce
                  moments about  any chosen centre. Thus, the total nose up moment on the wing
                  section is
                                 M  = Myy + Myj + Mjj + M,a + Mbd! + Mcii           (13.61)
                  where
                                              Myy = lypc2 V2y/c
                                              ~~j  = iypc3 v$lc
     	
