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GRAPHICAL SENSITIVITY ANALYSIS  93


                                      If C S is changed to 13 and simultaneously C D is changed to 8, the new objective
                                      function slope will be given by:
                                                                   C S   13
                                                                      ¼     ¼ 1:625
                                                                   C D    8
                                      Because this value is less than the lower limit of  1.5, the current solution of
                                      S ¼ 540 and D ¼ 252 will no longer be optimal. By re-solving the problem with
                                      C S ¼ 13 and C D ¼ 8 we will find that extreme point › is the new optimal
                                      solution.
                                         Looking at the ranges of optimality, we concluded that changing either C S to $13
                                      or C D to $8 (but not both) would not cause a change in the optimal solution. But in
                                      recalculating the slope of the objective function with simultaneous changes for both
                                      C S and C D , we saw that the optimal solution did change. This result emphasizes the
                                      fact that a range of optimality, by itself, can only be used to draw a conclusion about
                                      changes made to one objective function coefficient at a time.

                                      Right-Hand Sides
                                      Let us now consider how a change in the right-hand side of a constraint may affect
                                      the feasible region and perhaps cause a change in the optimal solution to the
                                      problem. To illustrate this aspect of sensitivity analysis, let us consider what happens
                                      if an additional ten hours of production time become available in the cutting and
                                      dyeing department of GulfGolf. The right-hand side of the cutting and dyeing
                                      constraint is changed from 630 to 640, and the constraint is rewritten as:
                                                                    0:7S þ 1D   640
                                      By obtaining an additional ten hours of cutting and dyeing time, we expand the
                                      feasible region for the problem, as shown in Figure 3.3. With an enlarged
                                      feasible region, we now want to determine whether one of the new feasible
                                      solutions provides an improvement in the value of the objective function. Appli-
                                      cation of the graphical solution procedure to the problem with the enlarged
                                      feasible region shows that the extreme point with S ¼ 527.5 and D ¼ 270.75 now
                                      provides the optimal solution. The new value for the objective function is
                                      10(527.5) + 9(270.75) ¼ $7711.75, with an increase in profit of $7711.75
                                      $7668.00 ¼ $43.75. Thus, the increased profit occurs at a rate of $43.75/10
                                      hours ¼ $4.375 per hour added.
                                         Although we used a graphical approach here to undertake sensitivity analysis on
                                      the cutting and dyeing constraint, it is actually easier to use the relevant equations.
                                      We know that for the GulfGolf problem, the optimal solution is at the intersection
                                      of the cutting and dyeing constraint line and the finishing constraint line. So, we
                                      have (as in Chapter 2):



                                                                    0:7S þ 1D ¼ 630                     ð3:5Þ
                                                                 1S þ 0:6667D ¼ 708                     (3:6)


                                      at the current optimal solution. If we now want to do a sensitivity analysis on the
                                      cutting and dyeing constraint (3.5) we can re-write the equation as:



                                                                    0:7S þ 1D ¼ 631                     (3:7)






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