Page 243 - Analog and Digital Filter Design
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240 Analog and Digital Filter Design




                       equations to find the VS WR are different. Let XI be the reactance of the shunt
                       arm and X2 be the reactance of the series arm. These reactance values must be
                       scaled in the same way as described for the type A network.

                       The  real part  of  the  impedance seen looking into  the  matching network is
                       given by:

                              R = sgn
                                     (X1+ 12)' + RL
                       The imaginary part is now given by:
                                        (X1+ X2) + RL ' I
                                    [
                              I=sgn   XI .(RL2 + X2 .(X1+ X2))


                       The reflection coefficient, and hence the  VSWR, can be found using the same
                       equations as for the type A network.

                       VSWR of T Matching Networks
                       Matching T networks can be broken down into real and imaginary impedance,
                       looking towards the load. The real impedance is given by:

                                         X22. R,'
                              R=sgn                 1
                                     (X2 + X3)'  + RL'
                       The imaginary impedance is:

                                    [       (X2 + X3)'  + RL2
                              I = sgn  XI + (X2. RL2 + X2 .X3.(X2 + X3))  1


                       The reflection coefficient, and hence the VSWR, can be found using the same
                       equations as for the type A network.


                       VSWR  of  PI Matching Networks
                       Matching PI networks can be broken down into real and imaginary impedance,
                       looking from the source into the load. The real impedance is given by:
                                    [ ((Xl+X2).X3)' +((XI+X2+X3).RL)' 1
                                                X1'.X3'.RL
                              R=sgn


                       The imaginary impedance is more complicated to show, because of the number
                       of terms. I have broken the numerator into two equations, which must be added
                       together.
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