Page 165 - Analysis and Design of Machine Elements
P. 165

Belt Drives
                          3  A belt drive can transmit a maximum power of P = 3 kW. The driving sheave has a  143
                                                                          −1
                             diameter of d = 150 mm, rotating at n = 1420 r min .Thecontact angleonthe
                                        1                     1
                                                   ∘
                             driving sheave is    = 160 . The coefficient of friction between the belt and belt
                                             1
                             sheave is 0.3. Decide the maximum effective force F and tight side tension F .
                                                                        ec                   1
                          4  A single belt drive with an initial tension of F = 300 N has a contact angle of
                                                                     0
                                    ∘                                       −1
                                = 150 on the small drive. The belt speed is v = 8ms . If the equivalent coef-
                              1
                             ficient of friction between the belt and belt drive is f = 0.5, neglecting centrifugal
                             force, decide the maximum power P thebeltdrive cantransmit.
                                                             ∘
                          5  A belt drive has contact angles of 180 on the driving and driven sheaves with an
                             initial tension of F = 150 N. The equivalent coefficient of friction is 0.5. Neglecting
                                            0
                             centrifugal force, if the transmitted effective force is F = 180 N, decide whether the
                                                                         e
                             belt will slip and explain why.
                          Design Problems
                          1  Design a V-belt drive for a 5.5 kW motor running at 1440 rpm driving an air com-
                             pressor at 520 rpm. Ensure it has the shortest possible centre distance.
                          2  A single V-belt is selected to deliver 3 kW engine power to a tractor. Approximately
                             70% of this power is transmitted to the belt. The maximum engine speed is 3000 rpm.
                             The driving sheave has a diameter of 150 mm, the driven, 300 mm. The belt selected

                             should be as close to a 2300 mm datum length as possible. Select a satisfactory belt.
                          3  A 1.5 kW electric motor running at 1460 rpm is to drive a blower at a speed of
                             240 rpm. Select a V-belt drive for this application and specify standard V-belts,
                             sheave sizes and centre distance.
                          4  The compressor of a small air-conditioning unit requires a 1.5 kW, 1200 rpm motor.
                             The speed of compressor is 300 rpm. The centre distance should be minimized to
                             provide a compact design. Design a suitable V-belt drive.


                          Structure Design Problems

                          1  On a V-belt drive in Figure P6.1, the angle between the two working surfaces of
                                              ∘
                             the V-belt is    = 40 , then the corresponding angle on the sheave groove    is
                                                                                               1
                                       ∘
                             ________40 .
                             (a) >
                             (b) <
                             (c) =
                          2  In Figure P6.2, which one best depicts the position of a V-belt in a sheave groove?
                             ______.
                          3  Figure P6.3 is a layout of power transmission. Find the errors and correct them.

                          4  For the tensioning scheme shown in Figure P6.4, part (a) is for a flat belt, while
                             (b) is for a V-belt. Make corrections where you see the errors occur.
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