Page 70 - Analysis and Design of Machine Elements
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Analysis and Design of Machine Elements
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                       Figure E2.2 An initial design of a shaft.


                         Solution



                        Steps      Computation                             Results      Units

                       1. Calculate  The stress at the cross section H:       = 5.48    MPa
                                                                            a
                       working stress  As the shaft rotates, bending stress     produced  MPa
                                                             bending          = 0.26
                                                                            m
                                   by constant moment M is a completely reversed     =    = 5.5  MPa
                                   stress; while axial stress     tension  is a static stress.  a  m
                                      =     bending  =5.48MPa
                                    a
                                       =      =0.26MPa
                                    m    tension
                                   Consider a unidirectional transmission, discontinuous
                                   working condition;    can be regarded as repeated
                                   stress.
                                             
                                      =    =  = 5.5MPa
                                        m
                                    a
                                           2
                                        2    −     2 × 275 − 500
                       2. Calculate     =  −1  0  =        = 0.1              = 0.1
                                                    500                       
                       coefficient           0
                                       2   −1  −    0  2 × 155 − 295          = 0.05
                                                                              
                                      =        =           = 0.05
                                      
                                             0      295
                       3. Calculate  The actual number of cycles               = 285.2  MPa
                                                                            −1N
                       endurance   N =8 × 60n × 300 × 2.5=7.2×10 6
                       strength    since                                       = 160.7  MPa
                                                                            −1N
                                     3
                                   10 < N < N = 10 7
                                            0
                                   We need to calculate the strength by finite life.
                                           √          √
                                            m N 0         10 7
                                       =        = 275 ×  9     = 285.2 MPa
                                    −1N   −1  N         7.2 × 10 6
                                           √          √
                                           m N 0          10 7
                                      −1N  =    −1  = 155 ×  9  = 160.7 MPa
                                             N          7.2 × 10 6
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