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10. Molecular Phylogeny
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                                                             root



                                                        1            2
                                    FIGURE 10.1. The Only Rooted Tree for Two Contemporary Taxa

                              the tree or speciation events (internal nodes) from which two new taxa
                              bifurcate.
                                The first theoretically interesting question about evolutionary trees is
                              how many trees T n there are for n contemporary taxa. For n = 2, obviously
                              T n = 1; the single tree with two contemporary taxa is depicted in Figure
                              10.1. The three possible trees for three contemporary taxa are depicted
                                                              (2n−3)!
                              in Figure 10.2. In general, T n =       . Thus, T 4 = 15, T 5 = 105,
                                                             2 n−2 (n−2)!
                              T 6 = 945, and so forth.

                                      root                  root                 root






                                 1      2     3        1     2      3       1      3     2


                                  FIGURE 10.2. The Three Rooted Trees for Three Contemporary Taxa

                                To verify the formula for T n , first note that an evolutionary tree with n
                              tips has 2n − 1 nodes and 2n − 2 edges. This is certainly true for n =2,
                              and it follows inductively because every new tip to the tree adds two nodes
                              and two edges. The formula for T n is proved in similar inductive fashion.
                              T 2 =(2 · 2 − 3)!/(2 2−2 0!) = 1 obviously works. Given a tree with n tips, tip
                              n + 1 can be attached to any one of the existing 2n − 2 edges or it can be
                              attached directly to the root if the current bifurcation of the root is moved
                              slightly forward in time. Thus,

                                               T n+1  =(2n − 1)T n
                                                         (2n − 1)(2n − 3)!
                                                     =
                                                           2 n−2 (n − 2)!
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