Page 142 - APPLIED PROCESS DESIGN FOR CHEMICAL AND PETROCHEMICAL PLANTS, Volume 1, 3rd Edition
P. 142

128                      Applied Process Design for Chemical and Petrochemical Plants

               5. Two-phase flow for horizontal flows:             lent flow, (b) sub-atmosphere pressure, (c) pressure drop
                                                                   is limited to  10% of  the final pressure  (see comment to
                  APTP = APGQ‘GT~ = (0.0254) (1.31)2 = 0.0438 psi/ft   follow), and  (d) the  lower  limit for  application  of  the
                                                                   method is
               6. F,  = 0.00967 (Wm)0.3/v0.7
                    = 0.00967 ( 19,494)0.5/(211)0.7                  W/d7  20                                  (2-125)
                    = 0.032

                  Vertical elevation pressure drop component:      where W is the flow rate in Ibs/hr  and d is the inside pipe
                                                                   diameter in inches. If  the above ratio is less than 20, the
                  = n h F,pL/144  = [(3) (10) + (1)  (SO)] (0.032) (63)/144   flow is “streamlined” and the data does not apply.
                  = 1.125 psi total                                  If  the pressure  drop is greater  than  10% of the final
                                                                   pressure, the pipe length can be divided into sections and
                  Total:                                           the calculations made for each  section, maintaining  the
                                                                   same criteria of (c) and (d) above.
                  APph = (0.0438) (358) + 1.125
                       = 16.7 psi, total for pipe line
                                                                   Method [54]
                Because  these  calculations  are  somewhat  uncertain
             due  to lack  of  exact correlations, it is  best  to  calculate   The method solves the equation  (see Figure 2-43)
             pressure drop for other flow patterns, and apply a gener-
             ous safety factor to the results.
                Table 2-20 gives calculated results for other flow pat-                                        (2 - 126)
             terns in several different sizes of lines.

                                                                   where  AP”,,  = pressure drop, in. water/100  ft of pipe
                                  Table 2-20
                           Two-Phase Flow Example                          p1 = initial pressure, inches mercury absolute
                                                                           Fl = base friction factor, Figure 2-43
               Pipe I.D.  1 Annular 1   Strati-   I   1  Eleva- 1  I      CT1 = temperature correction factor, Figure 2-43
                        1  Horizoytal Flow Pattern
                                                                           F,  = base friction factor, Figure 2-43
                                  fied  1  Wave  1  ‘$”.”
                                                 Factor,  Ft./sec..
                                                                          CT2 = temperature correction factor, Figure 2-43
                Inches
                         Psi/Ft.
                                 Psi/Ft.
                                         Psi/Ft.
               4.026  1  0.0110  1  0.0002431  0.0336  1  :::si5  1  I--   Gas Vel.   CDl = diameter correction factor, Figure 2-43
                                                I
                                        I
                                I
                        I
                                 0.000367  0.131
                                                          210.9
               3.068
                         0.0438
                        1  0.000062 I  0.000062 1  0.00035 I  0.166  I   31.1
                                                           53.9
               6.065     0.00128   0.000131  0.00434   0.0826   122.5     C,,   = diameter correction factor, Figure 2-43
                                                 0.121
                                 0.000087  0.00110
                         0.00027
                                                           19.7
                                                                   Example 2-17: Line Sizing for Vacuum Conditions
                                                                      Determine  the  proper  line  size for a  350 equivalent
                                                                   feet vacuum jet suction line drawing air at 350”F, at a rate
                        Pressure Drop in Vacuum Systems            of 255 lbs/hr  with an initial pressure at the source of 0.6
                                                                   in. Hg. Abs. Assume 10-in. pipe reading Figure 2-43. Note:
                Vacuum in process systems refers to an absolute pressure   watch scales carefully.
              that is less than or below the local barometric pressure at
              the location. It is a measure of the degree of removal of   F,  = 0.0155
              atmospheric pressure to some level between atmospheric
              barometer  and  absolute  vacuum  (which  cannot  be    F,  = 0.071
              attained  in  an absolute value  in  the  real world), but is   CD1 = 0.96
              used for a reference of measurement. In most situations,   CDz  = 0.96
              a vacuum is created by pumping air out of the container   CT1 = 1.5
              (pipe, vessels) and thereby lowering the pressure. See Fig-
              ure 2-1 to distinguish between vacuum gauge and vacuum   CT2  = 1.67
              absolute.                                             APmc  = [(0.0155) (0.96) (1.5) + (0.071) (0.96) (1.67)1/0.6
                This method  [54] is for  applications involving air or   = (0.02232 + 0.1138)/0.6
              steam in cylindrical piping under conditions of (a) turbu-   = 0.2269 in. water/100 ft.
   137   138   139   140   141   142   143   144   145   146   147