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               124     CHAPTER 4 CONTINUOUS RANDOM VARIABLES AND PROBABILITY DISTRIBUTIONS


                                   2.0
                                                                 λ
                                                                 2
                                                                0.5
                                   1.6
                                                                0.1

                                   1.2
                                 f(x)

                                   0.8
                                                                         f (x)

                                   0.4



                                   0.0
                                      0    2    4    6     8   10    12
                                                     x                                      0.1       x
                                 Figure 4-22 Probability density function of expo-  Figure 4-23 Probability for the expo-
                                 nential random variables for selected values of  .  nential distribution in Example 4-21.




                                 Also, the cumulative distribution function can be used to obtain the same result as follows:

                                                       P1X   0.12   1   F10.12   e  2510.12

                                    An identical answer is obtained by expressing the mean number of log-ons as 0.417 log-
                                 ons per minute and computing the probability that the time until the next log-on exceeds 6
                                 minutes. Try it.
                                    What is the probability that the time until the next log-on is between 2 and 3 minutes?
                                 Upon converting all units to hours,

                                                                 0.05                 0.05
                                                                       25x        25x
                                            P10.033   X   0.052    25e     dx   e     `    0.152
                                                                                      0.033
                                                                0.033
                                 An alternative solution is

                                                P10.033   X   0.052   F10.052   F10.0332   0.152

                                    Determine the interval of time such that the probability that no log-on occurs in the inter-
                                 val is 0.90. The question asks for the length of time x such that P1X   x2   0.90 . Now,

                                                            P1X   x2   e  25x    0.90


                                 Take the (natural) log of both sides to obtain  25x   ln10.902   0.1054 . Therefore,

                                                         x   0.00421 hour   0.25 minute
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