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190     Chapter 5/Joint Probability Distributions


                                   Because the integral gives the probability that Y # a for all values of a contained in the feasible
                                                     ⎡
                                   set of values for y,  f X ( )⎤ ⎦  ′(
                                                     u y u y) must be the probability density of Y. Therefore, the prob-
                                                     ⎣
                                   ability distribution of Y is
                                                          f Y ( y) =  f X ( )⎤ ⎦  ′(  f X ( )⎤ ⎦
                                                                    u y u y) =
                                                                                 ⎡
                                                                   ⎡
                                                                                  u y J
                                                                                 ⎣
                                                                   ⎣
                                   If the function y = h(x) is a decreasing function of x, a similar argument holds.
              Example 5-35     Function of a Continuous Random Variable  Let X be a continuous random variable with
                               probability distribution
                                                     f X ( x) =  x  , 0 ≤  x < 4
                                                            8
                 Find the probability distribution of Y = h(X) = 2X + 4.
               Note that y = h(x) = 2x + 4 is an increasing function of x. The inverse solution is x = u(y) = (y – 4) / 2, and from this,

               we ind the Jacobian to be J = u′(y) = dx / dy = 1 / 2. Therefore, from Equation 5-31, the probability distribution of Y is
                                                          ⎛ ⎞
                                           f Y ( y) =  ( y − ) 4  / 2 1  =  y − 4  ,  4 ≤  y ≤ 12

                                                          ⎜ ⎟
                                                     8    ⎝ ⎠ 2  32
               EXERCISES            FOR SECTION 5-5



                  Problem available in WileyPLUS at instructor’s discretion.
                           Tutoring problem available in WileyPLUS at instructor’s discretion

               5-79.   Suppose that X is a random variable with probabil-  5-85.   Suppose that X has the probability distribution
               ity distribution                                      f X ( x) = 1 ,  1 ≤  x ≤ 2
                    f X ( x) = 1 / , 4  x = 1 2 3 4             Determine the probability distribution of the random variable Y = e .
                                                                                                            X
                                    , , ,
               Determine the probability distribution of Y = 2X + 1.  5-86.     The random variable X has the probability distribution
               5-80.  Let X  be a binomial random variable with p  = 0.25 and     f X ( x) =  x  ,  0  ≤  x ≤ 4
               n = 3. Determine the probability distribution of the random vari-  8
                                                                                                      2
               able Y = X . 2                                   Determine the probability distribution of Y = (X – 2) .
               5-81.   Suppose that X  is a continuous random variable  5-87.  An aircraft is l ying at a constant altitude with veloc-
               with probability distribution                    ity magnitude r 1  (relative to the air) and angle θ 1  (in a two-
                    f X ( x) =  x  ,  0 ≤  x ≤ 6                dimensional coordinate system). The magnitude and direction
                         18                                     of the wind are r 2  and θ 2 , respectively. Suppose that the wind
               (a) Determine the probability distribution of the random vari-  angle is uniformly distributed between 10 and 20 degrees and
                  able Y = 2X + 10.                             all other parameters are constant. Determine the probabil-
               (b) Determine the expected value of Y.           ity density function of the magnitude of the resultant vector
                                                                         rr (cos 1 θ
                                                                                        . 0 5
               5-82.  Suppose that X has a uniform probability distribution  r = [ 1 2  r + 1 2  − cosθ 2 )] .
                                                                       2
                                                                   r + 2
                    f X ( x) = 1 ,  0  ≤  x ≤1                  5-88.  Derive the probability density function for a lognormal
               Show that the probability distribution of the random variable Y   random variable Y  from the relationship that Y = exp( ) for a
                                                                                                       W
               = –2 X is chi-squared with two degrees of freedom.  normal random variable W with mean θ and variance ω .
                                                                                                        2
               5-83.     A random variable X has the probability distribution  5-89.  The computational time of a statistical analysis applied
                          −
                           x
                    f X ( x) =  e ,  x ≥ 0                      to a data set can sometimes increase with the square of N, the
               Determine the probability distribution for the following:  number of rows of data. Suppose that for a particular algo-
                                                                                                         2
                     2
               (a) Y = X     (b) Y = X  / 1 2  (c) Y = ln X     rithm, the computation time is approximately T = .0 004 N  sec-
               5-84.     The velocity of a particle in a gas is a random vari-  onds. Although the number of rows is a discrete measurement,
               able V with probability distribution             assume that the distribution of N over a number of data sets can
                           2
                    f v ( ) =  av e − bv  v > 0                 be approximated with an exponential distribution with a mean
                    V
               where b is a constant that depends on the temperature of the gas   of 10,000 rows. Determine the probability density function and
               and the mass of the particle.                    the mean of T .
               (a) Determine the value of the constant a.       5-90.  Power meters enable cyclists to obtain power meas-
               (b) The kinetic energy of the particle is W =  mV / 2. Determine   urements nearly continuously. The meters also calculate the
                                                 2
                  the probability distribution of W.            average power generated over a time interval. Professional
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