Page 119 - Basic physical chemistry for the atmospheric sciences
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Oxidation-reduction  reactions            1 0 5

            oxidant is reduced, that is, it gains electrons).  Similarly, if a substance
            A  causes  the  reduction  of  substance  B ,   substance  A  is  called  the
            reducing agent or reductant.  In  Eq.  (6. 3 )  Cu(s)  is  the  reductant,  be­
            cause  it causes  Ag + (aq)  to  gain  electrons  (note  that  the reductant i s
                         i
            oxidized, that  s ,   it loses electrons). 1


                                 6.2  Oxidation  numbers
            In  order  to  deal  with  oxidation-reduction  reactions  that  are  more
            complex than the  simple ones discussed so far,  we must introduce the
            concept  of oxidation  numbers  (sometimes  called  oxidation  states  or
            valence states).  Oxidation numbers permit us to identify  and balance
            redox reactions and to determine the oxidant and reductant.
              Consider  the  redox  reaction  in  solution  of the ferric  ion  Fe 3  + (aq)
            and hydrogen sulfite HS0 3 (aq)
                                3
                            2Fe + ( aq) + H  S 0  3 (aq) + H20(1)-
                            2Fe 2  +  (aq) + HSO 4 (aq) + 2H + (aq)   (6.4)

            The half-reactions are
                     HS0 3 ( aq) + H20(1)- HS0  4 ( aq) + 2H + ( aq) + 2e -  (6.5)

            and,
                                                   2
                              2Fe3 + (aq) + 2e - - 2Fe + (aq)         (6.6)
            In this case,  it  is d i fficult to say exactly where the two electrons on the
            right side of Reaction (6.5) come fro m  .   Therefore,  we need a  method
            for keeping track of the electrons in reactions such as th s .   This can be
                                                              i
            done  by  making  some  assumptions.  It  is  assumed  that  the  h y drogen
            atom  in  HS0 3 (aq)  carries  one  unit of positive charge,  and  that each
            oxygen  atom  carries  two  units  of  negative  charge.  Since  the  total
            charge  on  HS0 3 (aq)  is  one  unit  of negative  charge,  the  charge  on
            the  sulfur  atom  is  four  units  of  positive  charge.  [Charge  on  sulfur
            atom  =  molecular charge  - charge  on one hydrogen atom  - charge
                                                          4
                                      - 1  - 1  - 3( - 2)  =  +  . ]   This  fictitious
            on  three  oxygen  atoms  =
            charge is called the oxidation number  of sulfur in HS0 3 (aq).
              Following  the  same  procedure,  the  oxidation  number  of  sulfur  in
            HS0 4 ( aq)  is:  -  1   -  1   -  4 ( -  2 )  =  +  6 .  Thus, according to this method
            of bookkeeping,  the two electrons  on  the right  side of Reaction (6. 5 )
            originate  from  the  sulfur  atom,  which  changes  its  oxidation  number
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