Page 123 - Basic physical chemistry for the atmospheric sciences
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Oxidation-reduction  reactions            1 0 9

                  balance  the  hydrogen atoms.  02 and  H2 are  not  used  to  bal­
                  ance the oxygen and hydrogen atoms unless they are  known
                                                               s
                  to  participate  in  the  reaction.  For  basic  solution ,   OH - (aq)
                  can  be  used  to  balance  the  half-reactio s .   For  each  excess
                                                       n
                  oxygen atom on one side of the equation, balance is achieved
                  by  adding  one  H20  to  the  other  side .  Hydrogen  balance  is
                  achieved by adding one OH - for each excess hydrogen atom
                  on the same side of the equation as the excess exists, and one
                  H 0  on  the  other  side  of the  equation.  If both  oxygen  and
                    2
                  hydrogen  atoms are i n   excess on the  same side of the equa­
                  tion ,  add  an  OH - on the other side of the equation for each
                  pair of oxygen and hydrogen atoms that are in excess. ]
           Step 4.  For each of the half-reaction ,   balance the electric charge  by
                                            s
                  adding electrons to the right side of the oxidation half-reaction
                  and to the left side of the reduction half-reaction.
           Step 5.  Multiply each half-reaction by a number that makes the total
                  number of electrons lost by the reductant equal to the number
                  of electrons gained by the oxidant.
           Step 6.  Add the  two half-reactions to get  the  overall reaction.  (Cancel
                  any  terms  that are  identical on both  sides  of the reaction;  all
                  electrons should cancel . )
           Step  7 .   Check  the  overall  reaction  for conservation  o f   the  atoms  of
                  each element and net charge.

             The following two exercises  l lustrate the application of this method,
                                      i
           first to an acidic reaction and then to a basic reaction.
             Exercise 6.2.  Balance  the  equation for  the  following redox reaction
           in an aqueous solution




             Solution.
           Step  I .   The  unbalanced equation  is  given above, which,  for  an  aque­
           ous solution, may also be written

                     +
                   H  ( aq) + N0 3(aq) + H S(aq)- NO(g) + S(s) + H20(1)   (6.7)
                                       2
                                                 i
                                                                   u
           Step 2 .   The oxidant is NO  ] (aq),  because  t   conta n s   N  ,   which  n der­
                                                       i
           goes  a  decrease  in  oxidation  number  [from  + 5  on  the  right  side  of
           Reaction  (6.7)  to  + 2  on  the  left  side].  Therefore,  the  unbalanced
           reduction half-reaction is
                                  N0 3 (aq)- NO(g)                  (6.7a)
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