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1 3 6               Basic physical chemistry

            6 . 2 9.   What  is  the  normality  of  1 . 0  L  of a  solution  that  contains
                      35.6 g of HN03 if the only chemical reaction is ionization?


                                         Notes
              The  reader  might wonder why  a reaction  such as (6.3), which does  not involve
              oxygen, is called an oxidation-reduction reaction. The reason is as follows.
              Originally the term  "oxidation" was applied to reactions in which a  substance
              combines with oxygen ,  for example, the oxidation of copper in air
                                   2Cu(s) + 02(g) _,. 2Cu0(s)
              This reaction involves each copper atom losing  two electrons, and each oxygen atom
              gaining two electrons
                                              +
                                   2Cu(s)_,. 2Cu2  ( aq) + 4e -
                                02(g) +  4e  -  __,. 202 - (aq)
                                                     2
                       Net:   2Cu(s) + Oi(g) _,. 2Cu 2  + (aq) + 20 - (aq)_,. 2Cu0(s)
              Thus, by analogy ,  all chemical reactions involving simultaneous electron loss and
              electron gain came to be called  oxidation-reduction reactions.
            2  From the  viewpoint of atomic structure,  every atom consists of a positive  nucleus
              surrounded by negative electrons.  In forming chemical bonds, atoms donate ,  receive,
              or share electrons. The number of electrons of an atom  that  is involved in this way in
              forming  bonds with other atoms is the oxidation number of the atom. A  positive
              oxidation number indicates that  the  atom has donated one or more electrons (e.g. ,
              +  I  for  the  hydrogen  atom  in  a  molecule), and a negative oxidation number indicates
              that the atom has received one or more electrons  (e.g.,  - 2 for the oxygen atom  in a
              molecule).
            3  In  redox reactions  it  is better to indicate  the  aqueous proton by H  ( aq) rather than
                                                             +
              by H,O + (aq), since it decreases  the number of water molecules that must be written .
            4  For example,  in  the  half-cell on  the  right  side of Figure 6. 1 ,   Cu 2  +  (aq)  ions are
              released from  the  copper electrode  into  the  solution. These attract SOi - (aq) ions
              with which they combine:  Cu2 + (aq) +  S  o� - (aq)_,. CuS04(aq). This would  leave  the
              solution with a  net positive charge if it were  not for negative ions drifting into this
                                                                 .
              half-cell from  the salt bridge.  In the half-cell on the left  side of Figure 6 1 ,   Ag + (aq)
              ions from  the solution are deposited onto the silver electrode .  This leaves  N  0  3 ( aq)
              ions in  the  vicinity of this electrode ;  these  attract  Ag + (aq) ions with which they
              combine:  NO ) (aq) +  A  g  + (aq)->  A  gN03(aq).  Again, the cell is maintained electrically
              neutral by positive  ions drifting into it from the salt bridge.
            5  A  I  M  solution is in  its standard  state only if it behaves ideally  (see Section 4.4), but
              this complication need  not  concern us here.
                                                                        23
            6  The  number of electrons in  I  mole of electrons is Avogadro's number (6.0229 x  10 ) ,
                                                                        o
              and the  charge o n   one electron is  1 . 602 1 x 1 0 - 19 coulombs. Therefore,  the charge  n
                   o
              I  mole  f   electrons is (6.0229 x 1023) x  1 .602 1 x 1 0 - 19)  r   %,489 coulombs; this is the
                                                     o
                                         (
              Faraday constant (F).
            7  The  following  is  an alternative explanation for the  fact  that type (a)  combinations are
              significant (i.e . ,   spontaneous) and type (b)  combinations are not .  In  type (a)
              combinations the better oxidant serves as  the oxidant, and the better reductant
              serves as  the reductant.  However, in type (b) combinations the better oxidant is
              forced into the role of a reductant and the better reductant into the role of the
              oxidant.
            8  Of course, c1 - ( aq) will react with Fe3 + (aq) until a small amount of Cl2(g) is formed
              to bring  the reaction to equilibrium. Therefore,  the phrase  "Cl  ( aq)  will  not react  to
                                                          -
                                                                    2
                                 3
              a  significant  extent  with  Fe + (aq)"  really  means "the ratio of [Cl(aq)] to [Fe + (aq))  is
              very  large at equilibrium."
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