Page 67 - Basic physical chemistry for the atmospheric sciences
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Chemical kinetics                   .'i i

            bimolecular  chemical  reaction  at  I  atm  and  0°C,  given  that  p =  3  x
            10-10 m and c  =  5 x 1 0  2   m s - 1  • How long would it  take to consume the

            reacting gases at this rate?
              Solution. We must first determine the number of molecules per unit
            volume (n0) of each gas at I  atm and 0°C. This can be found using the
            ideal gas equation in the form of Eq. ( l . 8g)
                                        p = n0kT

            where k is the Boltzmann constant. Substituting p  I   atm =  1 . 0 1   x 1 0 5
                                                         =
                                               g
            Pa,  T= 273K  and  k =    l . 3 x 8    1 0 -  23   J  de - 1   molecule-'  into  this equa­
                                      2
            tion, we obtain n0 = 2.68 x 1 0 5  m - 3 •  Hence, the total rate of collision
                                                  i
            ( i . e . , the maximum chemical reaction rate)  s   equal to
                                                        2
                                   10 2
             7Tp2cnAn8 = (3 . 1 4)(3 x  1 0 - ) (5 x 1 0 2)(2.68 x  1 0 25) molecules  -  3  s - 1
                                                                   m
                               = I  x    1035 molecule s  m  - 3  s _  ,
                                                            2
            Or,  since  there  are  Avogadro's  number ( = 6.022 x  1 0 3) of molecules
                                     3
            in I  mole, and  I  L =  10 - 3   m , the maximum chemical reaction rate is
                               3
                               1 0 5 x 1 0 - 3
                          I  x              1
                                    2
                           6_022 x 1 0 3   2 x  0 8  mol  liter- 1   s - 1
              The  time  required  to  consume  one  of  the  gases,  cons1stmg  of
                    2
                                   3
            2 . 6 8 x  1 0 5  molecules  m- ,   at  a  rate  of  I  x    1 0 35  molecules  m  - 3   s - 1
            would be
                                        2
                                 2. 6 8 x 1 0 5
                                 ---=-=-  =  3 x  1 0 -  10  s
                                  I  x    1 0 35
              Although a few chemical reactions actually proceed at the enormous
            rate calculated in Exercise  . 5 ,   most reactions occur at a much slower
                                    3
            rate.  Hence, factors other than the mere collisions of molecules must
            be  involved  in chemical  reactions.  Since the  rate  of many chemical
            reactions  varies  markedly  with  temperature,  we  must  now  consider
                                                      n
            how temperature may affect a chemical reactio .
              Shown in Figure  . 1  i s   the distribution of the kinetic energies of the
                              3
            molecules  in  a gas  for  two  temperatures.  The  number of molecules
            with kinetic energy  :=:::  Ea is proportional to the shaded area in Figure
               .   It  can  be seen that  if Ea  is  fairly large, the number of molecules
            3 . 1
            with energy  :=::: Ea is very sensitive to temperature.  Hence, if a certain
            minimum value of Ea is required for two colliding molecules to react
                     y
            chemicall ,   it  is apparent  why  the  chemical  reaction rate should be
            hoth  smaller and more  temperature sensitive than  the collision rate.
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