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76                  Basic physical chemistry

              define  it  in  terms  of the  activities  of  the  substances  (see  note  5  m
              Chapter  ) .
                      1
                Whenever the product of the concentrations of any two ions (raised
              to the appropriate powers) in a solution is less than the corresponding
              Ksp value, the solution is subsaturated.
                In Exercise  . 3   the ions in the saturated solution derive only from
                           4
              the  solid  solute.  However,  as  illustrated  in  the  next  two  problems,
              solubility  products can be used to calculate the solubility of a  sub­
              stance  in a  saturated  solution even if some of the  ions derive from
              another source.
                Exercise  4.4.  (a)  Calculate  the  molar solubility of silver chromate
              [Ag2Cr0is)] in water, given that the solubility product is 2 . 4   x 1 0 - 1 2 .
              (b)  Discuss  qualitatively  the  effects  of adding  some  CrO� - (aq)  ions
              from  another  source  to  a  saturated  solution  of silver  chromate  in
              water.
                Solution. (a) The reaction is
                             Ag 2 Cr0is) µ  2 Ag+ (aq) + Cro� - (aq)   (4. 1 3 )

              The solubility product is
                                      2                     2
                             [Ag + (aq)] [Cr0� - (aq)] = 2 .4 x  1 0 -  1  (4. 1 4 )
              We see from Reaction (4. 1 3 ) that when 1  mole of Ag 2 Cr0is) dissolves
              in water, 2  moles of Ag+(aq) and 1  mole of Cro�- (aq) appear in the
                             n
              saturated solutio .   Therefore,
                                  [Ag+(aq)]  =  2[Cro�- ( aq)]         (4. 1 5)

              From Eqs. (4 . 1 4 ) and (4. 1 5 )
                                         2
                            {2[Cro� - (aq)J} [Cr0(aq)] =  2 . 4   x  0 -1 2
                                                         1
              Therefore,  [C�- (aq)] = 0 .84 x  1 0 -  4  M.  S i nce, from Reaction  (4. 1 3 ) ,   l
              mole of silver chromate dissolves for every  l  mole of Cro�- (aq) that
              forms, the solubility of silver chromate in water is 0.84 x  1 0 -  4  M  .
                (b) I f   CrOi- ( aq) ions are added  o   the equilibrium situation repre­
                                             t
              sented  by  Reaction  (4. 1 3 ) ,   LeChatelier's  principle  tells  us  that  the
              reverse  reaction  in  (4. 1 3 )   will  be  favored.  This  means  that  some
              Ag2Cr04(s)  will  precipitate  out from  the  saturated  solution,  thereby
              reducing the concentration of Ag+ (aq).
                We  see  from  the  last problem that the addition to a saturated solu­
              tion of a  small quantity of another solution that contains one of the
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