Page 93 - Basic physical chemistry for the atmospheric sciences
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Solution chemistry and aqueous equilibria

             Weak electrolytes ionize incompletely in water. For example, accl i c
                                  l
           acid dissolves only partial y   in water (to form vinegar)



           but only a small fraction of the acetic acid forms ions in this way,  so
           the  solution  is  only  a  weak  electrical  conductor.  The  ionization  of
           CH3COOH(I)  represented  by  Reaction  (4 . 1 9 )  differs  from  that  of
                               .
           HCl(g)  in  Reaction  (4 1 8 )  in  a  significant  way;  namel ,   it  is  a  truly
                                                            y
           reversible  reaction  [indicated  by  the  two-way  arrows  in  Reaction
           (4. 1 9 )]  and  can  therefore  be represented  by an  equilibrium-constant
           expression.
             Water itself is a very weak electrolyte

                             H 2 0(1) � H + (aq) + OH -(aq)         (4.20)

           where  H + (aq)  and  OH -(aq)  are  the  hydrogen  and  hydroxide  ions,
           respectivel ,   in solution. The longer arrow from right to left in Reac­
                     y
           tion (4.20) can,  if desired,  be used to emphasize that there are many
           more  H 0  molecul e s  than  there  are  H + (aq)  and  OH - ( aq)  ions.  We
                  2
           could define an equilibrium constant for Reaction (4.20) by
                                    [H + (aq)][OH - ( aq)]
                                K  =                                (4. 2 1 )
                                        [HzO(I)]

           However,  the  concentration  of H 0  molecules  in  water  is  so  large
                                          2
           (55 . 5   M), and so few ions are formed that [H20(1)] is virtually constant.
           Therefore,  [H20(1)]  is  usually  combined  with K  and  called  the ion­
           product constant  o r water (Kw)
                          f
                                                                    (4.22)

           where,

                                                                      .
                                Kw = [H 0(1)]K = 55.5K              (4 2 3)
                                       2
           At  25°C,  Kw =  1 . 00 x 1 0 - 1 4  (when  concentrations  are  expressed  in
           moles per liter).
             Exercise 4.8.  What are the concentrations of H + ( aq) and  OH -(aq)
           in pure water at 25°C?
             Solution.  In pure water

                                 [H + (aq)] = [OH - ( aq)]
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