Page 118 - Calculus Demystified
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The Integral
CHAPTER 4
y = f (x) 105
x 0 = a x 1 x 2 x k = b
Fig. 4.5
y = f (x)
x 0 = a x 1 x 2 x k = b
Fig. 4.6
y = f (x)
a b
Fig. 4.7
The reasoning just presented suggests that the true area A is given by
lim R(f, P).
k→∞
We call this limit the integral of f from x = a to x = b and we write it as
b
f(x) dx.
a
