Page 243 - Calculus Demystified
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CHAPTER 8
                     230
                                   EXAMPLE 8.10                 Applications of the Integral
                                   Use the method of cylindrical shells to calculate the volume enclosed when
                                                2
                                   the curve y = x ,0 ≤ x ≤ 3, isrotated about the x-axis(Fig. 8.20).

                                                                 y












                                                                                x







                                                              Fig. 8.20



                                   SOLUTION
                                     We reverse, in our analysis, the roles of the x- and y-axes. Of course y
                                   ranges from 0 to 9. For each position y in that range, there is a segment stretch-
                                                √                                 √
                                   ing from x =   y to x = 3. Thus it has length 3 −  y. Then the cylinder
                                   generated when this segment (thickened to a strip of width  y) is rotated
                                   about the x-axis has volume

                                                                   
   √
                                                      V(y) = 2πy · 3 −   y   y.
                                   The aggregate volume is then

                                                       9
                                                             
   √
                                                V =     2πy · 3 −  y dy
                                                     0
                                                          9

                                                  = 2π ·    3y − y 3/2  dy
                                                          0
                                                            2    5/2    9
                                                          3y    y
                                                  = 2π ·      −        dy
                                                           2    5/2  0
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