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Chapter 12



                            Who Needs Freud? Using the



                         Integral to Solve Your Problems





                In This Chapter

                  Weird areas, surfaces, and volumes
                  L’Hôpital’s Rule
                  Misbehaving integrals
                  Other stuff you’ll never use




                               ow that you’re an expert at integrating, it’s time to put that awesome power to use to
                          Nsolve some . . . ahem . . . real-world problems. All right, I admit it — the problems you
                          see in this chapter won’t seem to bear much connection to reality. But, in fact, integration is
                          a powerful and practical mathematical tool. Engineers, scientists, and economists, among
                          others, do important, practical work with integration that they couldn’t do without it.


                Finding a Function’s Average Value



                          With differentiation, you can determine the maximum and minimum heights of a function, its
                          steepest points, its inflection points, its concavity, and so on. But there’s a simple question
                          about a function that differentiation cannot answer: What’s the function’s average height?
                          To answer that, you need integration.



                Q.   What’s the average value of sinx between  A.   Piece o’ cake. This is a one-step problem:
                     0 and π?
                                                                                                π
                                                                                               #  sinx dx
                                                                                 total area
                                                                    average value=           =  0
                                                                                   base         π -  0
                                                                                                    π
                                                                                              - cosx @
                                                                                             =   π  0
                                                                                                1 - -
                                                                                              - ^  1  1h
                                                                                             =    π
                                                                                              2
                                                                                             =
                                                                                               π
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