Page 56 - Calculus Workbook For Dummies
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40       Part II: Limits and Continuity



                                                               0
                          When plugging in fails because it gives you  , you’ve got a real limit problem, and you
                                                               0
                          have to convert the fraction into some expression where plugging in does work. Here
                          are some algebraic methods you can try:

                             FOILing
                             Factoring
                             Finding the least common denominator
                             Canceling
                             Simplification
                             Conjugate multiplication

                          The following examples each use a different method to solve the limit.



                Q.   Evaluate lim  16 -  x  .                  Q.   What’s  lim  x - -  6  ?
                                                                               2
                                                                                  x
                                                                               2
                                                                                  x
                             x " 16  4 -  x                               x " -  2  x + -  2
                A.   The limit is 8.                           A.   The limit is  5  .
                                                                               3
                        1. Try plugging 16 into x — no good.           1. Try plugging –2 into x — that gives
                                                                              0
                        2. Multiply numerator and denomina-               you  , so on to plan B.
                          tor by the conjugate of 4 -  x,                     0
                                                                       2. Factor and cancel.
                          namely 4 +  x.
                                                                                     2 ^
                          The conjugate of a two-term expres-               = lim  ^ x + h  x -  3h
                                                                                     2 ^
                          sion has a plus sign instead of a                  x " - ^ x + h  x -  1h
                                                                                2
                          minus sign — or vice-versa.                            ^ x -  3h
                                                                            = lim
                                                                             x " - ^ x -  1h
                                                                                2
                              ^ 16 -  xh  ` 4 +  xj
                           lim        $                                3. Cancel now and plug in.
                           x "  16  4 -  xj  4 +  xj
                              `        `
                                                                             - 2 -  3
                                                                            =
                        3. FOIL the conjugates and simplify.                  - 2 -  1
                                                                             - 5
                                                                            =
                                                                             - 3
                                  x 4 +
                              ^ 16 - h `  xj Because,
                         = lim                                              =  5
                           x "  16  2   2    of course,                       3
                                 c 4 -  x m
                                             ^ a - h ^  b =
                                                 b a + h
                                              2
                                  x 4 +
                              ^ 16 - h `  xj  a -  b  2 .
                         = lim
                           x "  16  ^ 16 -  xh
                         = lim 4 +  xj
                              `
                           x "  16
                        4. Now you can cancel and then
                          plug in.
                         = 4 +  16
                         = 8
                       Note that while plugging in did not work
                       in Step 1, it did work in the final step.
                       That’s your goal: to change the original
                       expression — usually by canceling — so
                       that plugging in works.
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