Page 79 - Corrosion Engineering Principles and Practice
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58    C h a p t e r   4                                                                                                   C o r r o s i o n   T h e r m o d y n a m i c s    59


                      for  pure  species  and  soluble  species  involved  in  the  equilibria
                      associated with aluminum, water, and oxygen. Table 4.5 contains the
                      chemical and electrochemical reactions possibly occurring in a typical
                      Al-air corrosion cell.
                         The  overall  anodic  reaction  of  the  aluminum-air  battery  is  the
                      corrosion  of  aluminum  into  a  soluble  form  stable  in  a  caustic
                                      −
                      environment, AlO  in Eq. (4.15), that can subsequently precipitate as
                                     2
                      Al O ·H O, as shown in Eq. (4.16), depending on the concentration of
                             2
                          3
                        2
                      ions in solution, pH, and temperature.
                                   Al +  4OH −  →  AlO 2 −  +  2H O +  3e    (4.15)
                                                               −
                                                         2
                                                                 −
                                                      ⋅
                                 2AlO 2 −  +  2H O →  Al O H O +  2OH      (4.16)
                                                     3
                                            2
                                                   2
                                                        2
                       Water equilibria
                       2 e  + 2 H  = H
                          −
                               +
                                   2
                       4 e  + O  + 4 H  = 2 H O
                          −
                                   +
                              2          2
                              +
                          −
                       OH  + H  = H O
                                  2
                       Equilibria involving aluminum metal
                       3 e  + Al  = Al
                              3+
                          −
                       3 e  + Al(OH)  + 3 H  = Al + 3 H O
                                       +
                          −
                                  3             2
                                        +
                       6e + Al O ·H O + 6 H  = 2 Al + 4 H O
                             2  3  2               2
                       3 e  + AlO  + 4 H  = Al + 2 H O
                                      +
                                −
                          −
                               2               2
                          −
                       3 e  + Al(OH)  + H  = Al + H O
                                  2+
                                      +
                                              2
                       3 e  + Al(OH)  + 2 H  = Al + 2 H O
                                        +
                          −
                                  +
                                  2              2
                       Equilibria involving solid forms of oxidized aluminum
                       Al(OH)  + H  = Al(OH)  + H O
                                        +
                                +
                            3           2   2
                                    +
                       Al O ·H O + 2 H  = 2 Al(OH)  +
                         2  3  2             2
                                         2+
                                  +
                       Al(OH)  + 2 H  = Al(OH)  + 2 H O
                            3                   2
                       Al O ·H O +  4 H  = 2 Al(OH)  + 2 H O
                                    +
                                              2+
                         2  3  2                    2
                       Al(OH)  + 3 H  = Al + 3 H O
                                      3+
                                  +
                            3               2
                                          3+
                                    +
                       Al O ·H O + 6 H  = 2 Al + 4 H O
                         2  3  2                2
                                  −
                       Al(OH)  = AlO  + H  + H O
                                      +
                            3     2       2
                       Al O ·H O = 2 AlO  + 2 H +
                                      −
                         2  3  2     2
                       Equilibria involving only soluble forms of oxidized aluminum
                           −
                       AlO  + 4 H  = Al  + 2 H O
                                    3+
                                +
                          2                2
                      TABLE 4.5  Reactions Describing the Chemistry of an Aluminum-Air
                      Corrosion Cell
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