Page 129 - Curvature and Homology
P. 129

3.7.  CONFORMAL TRANSFORMATIONS           111

       The  integral  of  the  left  side  of  (3.7.15)  over  M vanishes  by  Stokes'
       theorem. Hence, integrating  (3.7.15)  gives



       Thus,



       and  so,  since a and fl  are arbitrary
                        e(x),  + #(x)~ = (I  - :)   86 +  a.


         Let M be a Riemannian manifold, Co(M) the largest connected group
       of  conformal  transformations  of  M  and  Io(M) the  largest  connected
       group of  isometries of  M.  (Note that L  and K  are the Lie algebras of
       Co(M) and Io(M), respectively.)  We shall prove the following:

       Theorem  3.7.4.   Let M be  a compact Riemnnian ntanifold. If Co(M) #
       Zo(M), then, there is nu hamtonic form of  degree p, 0 < p < n (n = dim M)
       whose length is a non-zero constant  [78].
         Since a harmonic form on a compact Riemannian manifold is invariant
       by  Io(M),  a  harmonic  form  on  a  compact  homogeneous  Riemannian
       manifold (cf. VI. E) is  of  constant  length.  (A  Riemannian  homogeneous
       mansjCold is a Riemannian manifold whose group of  isometries is transi-
       tive.) Hence, as an immediate consequence of  theorem 3.7.4  we have

       Theorem 3.7.5.  Let M be  a  compact homogeneous Riemannian mat$old.
       If  Co(M) Sf. Io(M), then M is a homology sphere [78].
         Since  we  are  interested  in  connected, groups,  the  hypothesis  of
       theorem  3.7.4  may  be  replaced by  the fdlowing:  Let M be  a  compact
       Riemannian  manzjold  admitting  an injinitesinal  non-isometric  conformal
       transformation.  We may  also assume that M is orientable;  for,  if  M is
       not orientable, we need only take an orientable two-fold covering space
       of  M.
       Proof  of  Theorem  3.7.4.  Let  or  be a harmonic form of  degree p.  We
       shall first prove
                             (&x)  a, 0(X) a) = 0.
       Since  or  is  closed,  6(X) or  = di(X) a. On  the  other  hand,  since  a  is
       co-closed,  M(X) o: = &X) 601 = 0.  Thus,
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