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116   4. Particular Determinants

          where P m is the Legendre polynomial, then φ m satisfies (4.9.3) with
                                            2 −3/2
                                  F =(1 − x )
          and φ 0 = P 0 = 1, but φ m is not a polynomial. These relations are applied
          in Section 4.12.1 to evaluate |P m | n .

          Examples

          1. If
                                    1                  m+1
                                         k
                            φ m =          b r {f(x)+ c r }  ,
                                  m +1
                                        r=1
             where  k !  b r =0, b r and c r are independent of x, and k is arbitrary,
                  r=1
             then
                                φ    = mf (x)φ m−1 ,

                                 m
                                      k

                                 φ 0 =   b r c r = constant.
                                     r=1
             Hence, A = |φ m | n is independent of x.
          2. If
                             1         m+1          m+1          m+1
                 φ m (x, ξ)=     (ξ + x)   − c(ξ − 1)   +(c − 1)ξ    ,
                           m +1
             then
                                         = mφ m−1 ,
                                    ∂φ m
                                     ∂ξ
                                      φ 0 = x + c.
             Hence, A is independent of ξ. This relation is applied in Section 4.11.4
             on a nonlinear differential equation.


          Exercises
                                                         2
          1. Denote the three cube roots of unity by 1, ω, and ω , and letA = |φ m | n ,
             0 ≤ m ≤ 2n − 2, where
                        1              m+1            m+1    2      2  m+1
             a. φ m =         (x + b + c)  + ω(x + ωc)    + ω (x + ω c)   ,
                     3(m +1)
                        1              m+1    2        m+1          2  m+1
             b. φ m =         (x + b + c)  + ω (x + ωc)    + ω(x + ω c)   ,
                     3(m +1)
                            1              m+2    2       m+2          2  m+2
             c. φ m =                (x + c)   + ω (x + ωc)   + ω(x + ω c)    .
                     3(m + 1)(m +2)
             Prove that φ m and hence also A is real in each case, and that in cases
             (a) and (b), A is independent of x, but in case (c), A = cA 11 .
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