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184   5. Further Determinant Theory

                          n+1−j

                                ψ 2n−s δ s,n−j+1
                     = H n
                            s=1
                     = H n ψ n+j−1 ,  1 ≤ j ≤ n;                    (5.2.21)
                               2n−i−j+1
                        n                               s = t − j
                            (n)
                   Y i =   K           φ t+i+2 ψ 2n−s ,
                                                        s → t
                            jn
                       j=1     s=n+2−j
                               2n−i+1
                        n
                            (n)
                     =     K
                            jn       φ t+i−2 ψ 2n+j−t
                       j=1     t=n+2
                       2n−i+1       n
                                               (n)

                     =       φ t+i−2   ψ 2n+j−t K
                                               jn
                        t=n+2      j=1
                       2n−i+1       n
                                                  (n)
                     =       φ t+i−2   k j+n+1−t,n K
                                                  jn
                        t=n+2      j=1
                          2n−i+1

                                φ t+i−2 δ t,n+1
                     = K n
                           t=n+2
                     =0,   1 ≤ i ≤ n − 1,                           (5.2.22)
          since t>n + 1. Hence,
                                        n
                                             (n)
                                           K   ψ n+j−1
                               Pf n = H n
                                            jn
                                        j=1
                                        n
                                               (n)
                                           k jn K
                                  = H n
                                               jn
                                        j=1
                                  = H n K n ,
          which completes the proof of Theorem 5.1.
          5.2.4  Three Further Theorems
          The principal theorem, when expressed in the form
                            2n−1
                                    i+1  (n)
                                (−1)   Pf  a i,2n = H n K n ,       (5.2.23)
                                         i
                             i=1
          yields two corollaries by partial differentiation. Since the only elements
          in Pf n which contain φ 2n−1 and ψ 2n−1 are a i,2n ,1 ≤ i ≤ 2n − 1, and
            (n)                                    (n)
          Pf   is independent of a i,2n , it follows that Pf  is independent of φ 2n−1
            i                                      i
          and ψ 2n−1 . Moreover, these two functions occur only once in H n and K n ,
          respectively, both in position (n, n).
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