Page 231 - Dynamics of Mechanical Systems
P. 231

0593_C07_fm  Page 212  Monday, May 6, 2002  2:42 PM





                       212                                                 Dynamics of Mechanical Systems


                                              ( 92 − ) λ  − (  3 4)  ( 3 3 4)  
                                                                          
                                               − (  3 4)  ( 39 8 − ) λ  (  3 8)   =  0        (7.8.3)
                                               33 4)    (  3 8)   (       
                                                                         λ
                                              (                   37 8 − ) 

                       Expanding the determinant, we obtain:

                                                                 −
                                                     λ −  14 λ +  63 λ 90 =  0                  (7.8.4)
                                                           2
                                                      3
                       The coefficients of Eq. (7.8.4) are seen to be the parameters I , I , and I  of Eqs. (7.7.13),
                                                                               II
                                                                             I
                                                                                      III
                       (7.7.14), and (7.7.15).
                        By solving Eq. (7.8.4) we obtain:
                                                λ =  λ = 3,  λ =  λ = 5,  λ =  λ = 6            (7.8.5)
                                                     1         2        3
                       These are the principal moments of inertia. By substituting the first of these into Eq. (7.8.2),
                       we obtain:

                                              ( 92 3) +− (  3 4) ( 3 3 4) a 3  =  0
                                                  −
                                                                +
                                                              a
                                                     a
                                                      1
                                                               2
                                               − (  3 4) +( 39 8 3) (  3 8) a  =  0             (7.8.6)
                                                            −
                                                                 +
                                                               a
                                                   a
                                                    1           2        3
                                              ( 33 4) +(  3 8) a 2 ( 37 8 3)a 3  =  0
                                                                      −
                                                                +
                                                     a
                                                      1
                       By eliminating fractions we have:
                                                     2a − a +  3a =  0
                                                       1  2     3
                                                     − 6a + 15a +  3a =  0                      (7.8.7)
                                                        1    2     3
                                                     18a + 3a + 13 3a =  0
                                                        1   2       3
                       These equations are seen to be dependent (multiplying the  first by 12 and adding the
                       result to the second produces the third); hence, only two of the equations are independent.
                       A third independent equation may be obtained from Eq. (7.7.16) by requiring that n  be
                                                                                                   a
                       a unit vector:
                                                        a + a + a =  1                          (7.8.8)
                                                                 2
                                                             2
                                                         2
                                                         1   2  3
                       Thus, by selecting any two of Eq. (7.8.7) and appending them to Eq. (7.8.8) we can
                       determine a , a , and a . The result is:
                                 1
                                          3
                                    2
                                                a =  22,  a =  2 4,  a = −  6 4                 (7.8.9)
                                                 1        2         3
   226   227   228   229   230   231   232   233   234   235   236