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0593_C07_fm  Page 221  Monday, May 6, 2002  2:42 PM





                       Inertia, Second Moment Vectors, Moments and Products of Inertia, Inertia Dyadics  221


                       From Eq. (7.7.5), if n  is a principal unit vector, we have:
                                         a
                                                    ⋅
                                                   In = I  n    no sum on  a                   (7.9.38)
                                                      a   aa  a
                       The associated scalar equations, Eq. (7.7.10), then become:
                                                       11 (
                                                      I − ) +   I a =  0
                                                             a
                                                          I
                                                              1
                                                                 12 2
                                                           aa
                                                      Ia +( I − ) a =
                                                      21 1  22  I aa  2  0                     (7.9.39)
                                                       33 (
                                                      I − )  a =  0
                                                          I
                                                              3
                                                           aa
                       where, as before,  a ,  a , and  a  are the components of  n  relative to  n ,  n , and  n . By
                                                  3
                                        1
                                                                          a
                                                                                          2
                                                                                       1
                                           2
                                                                                                 3
                       inspection, a solution to these equations is:
                                                   I =  I ,  a = 1,  a =  a = 0                (7.9.40)
                                                   aa
                                                            3
                                                                      2
                                                                   1
                                                       33
                       If, however, I  is not equal to I , then a  is zero and the equations for a , a , and I  reduce to:
                                                        3
                                                                                      2
                                                                                            aa
                                                                                   1
                                  aa
                                                 33
                                                       11 (
                                                      I − ) +   I a =  0
                                                             a
                                                          I
                                                           aa
                                                                 12 2
                                                              1
                                                      Ia +( I − ) a =
                                                      21 1  22  I aa  2  0                     (7.9.41)
                                                     a +  a =  1
                                                          2
                                                      2
                                                      1   2
                       Because the first two of these equations are linear and homogeneous, the third equation
                       will be violated unless the determinant of the coefficients of the first two equations is zero.
                       That is,
                                                     11 (
                                                     I − )    I 12
                                                         I
                                                         aa
                                                                22 (
                                                    I          I − )  =  0                     (7.9.42)
                                                                   I
                                                     21             aa
                       Expanding the determinant we obtain:
                                                 I − (  I + ) +  I I − I =
                                                  2
                                                                       2
                                                  aa  I aa  11  I 22  11 22  12  0             (7.9.43)
                       Solving for I  we find:
                                  aa
                                                    I +  I    I −  I  2   12
                                                I =  11  22  ±    11  22  +  I            (7.9.44)
                                                                         2
                                                 aa                    12
                                                       2       2         
                        When I  has the values as in Eq. (7.9.44), the first two equations of Eq. (7.9.41) become
                               aa
                       dependent. Hence, by taking the first and third of Eq. (7.9.41) we have a  and a  to be:
                                                                                              2
                                                                                       1
                                                                    aa ]
                                                   a =  I 12 [ I +( I − ) 2  12                (7.9.45)
                                                            2
                                                                    I
                                                    1       12  11
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