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0593_C07_fm  Page 218  Monday, May 6, 2002  2:42 PM





                       218                                                 Dynamics of Mechanical Systems


                       Because I is symmetric we have:

                                                           α = β                               (7.9.23)
                                                             b   a

                       From Eq. (7.9.7), the invariants I , I , and I  are:
                                                      II
                                                   I
                                                            III
                                                  I = 3 I = α  + β  +  I
                                                  I        a  b
                                                       2
                                                 I = 3 I = β  I + α  I + α β  − α  2           (7.9.24)
                                                  II       b    a    a b   b
                                                                  2
                                                      3
                                                 I  =  I =  I(αβ  − α b)
                                                  III       a b
                       where the right sides of these expressions are obtained from the description of I , I , and
                                                                                              I
                                                                                                II
                       I  in Eqs. (7.7.13), (7.7.14), and (7.7.15) and from the matrix of I in Eq. (7.9.22). By solving
                       III
                       for α , α , and β , we obtain:
                                     b
                              b
                           a
                                                   α =  I,  α =  β = ,  β =  I                 (7.9.25)
                                                                  0
                                                    a      b   a      b
                       Hence, αα αα and ββ ββ are:
                                                    αα =  In     and    ββ =  In               (7.9.26)
                                                      a    a            b
                       Finally, I becomes (see Eq. (7.9.21)):

                                                    I = I n n + I n n + I n n                  (7.9.27)
                                                         a  a  b  b   c  c

                       Then, if ηη ηη is any vector:
                                                             η
                                                           I⋅= ηη                              (7.9.28)
                                                             η
                                                                I
                       Hence, when there is a triple root of Eq. (7.7.12) all unit vectors are principal unit vectors.
                        Regarding the question of real roots of Eq. (7.7.12), suppose a root is not real. That is,
                       let a root λ have the complex form:

                                                          λ =  α + i β                         (7.9.29)


                       where  α and  β are real and  i is the imaginary   −1.  Let  n be a principal unit vector
                       associated with the complex root λ. Then, from Eq. (7.7.5), we have:

                                                           In⋅= λ n                            (7.9.30)


                       By following the procedures of the previous sections we can obtain  n by knowing  λ.
                       Because λ is complex, the components of n will be complex. Then, n could be expressed
                       in the form:


                                                         n =  n + i n β                        (7.9.31)
                                                              α
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