Page 48 - Electric Machinery Fundamentals
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24  ELECTRIC MACHINERY FUNDAMENTALS

            nonlinearity accounts for many of the peculiar behaviors of machines that will be
            explained in future chapters. We will use MATLAB to calculate solutions to prob-
            lems involving the nonlinear behavior of real machines.

                 Example 1-4.  Find the relative permeability of the typical ferromagnetic material
            whose magnetization curve is shown in Figure I- lOe at (a) H  =  50, (b) H  =  100, (c) H  =
            500, aud (d) H  ~ 1000 A • turns/m.

                 Solution
            The permeability of a material is given by



            and the relative permeability is given by


                                                                      (1-23)
                                                                                (
            Thus, it is easy to determine the permeability at any given magnetizing intensity.
                 (a)  At H  ~ 50 A '  turns/m, B  ~ 0.25 T, so
                                        0.25 T
                                                ~ 0.0050 H/m
                                     50 A  • turns m
                                              /
            and
                               JL  ~ 1'0 ~  0.0050 Him   ~ 3980
                                 I   f.Lo   41T  X  10  7 Him
                 (h)  AtH ~ 100A '  tums/m,B ~ o.n T, so
                                 B
                              JL  ~ -H ~ 100 ~.n T  /  ~ 0.0072 H/m
                                          • turns m
            and
                                  ~ 1'0 ~  o.oon H/m   ~ 5730
                                f.Lr   f.Lo   41TXI07H/m
                 (c)  AtH ~ 500A'turns/m,B ~ 1.40T, so
                               ~ Ii ~   l AO T   ~ 0.0028 H/m
                              J.l.   H   500 A • turns/m
            and
                                JL  ~ 1'0 ~  0.0028 Him   ~ 2230
                                 r   flo   41T  X  10  7 Him
                 (d)  At H  ~ 1000 A • turns/m, B  ~ 1.51  T, so
                                B       1.51 T
                             JL  ~ H- ~ 1000 A   /   ~ 0.00151 H/m
                                          • turns m
            and
                                  ~ 1'0 ~  0.00151 Him  ~ 1200
                                Mr   f.Lo   41T  X  10  7 Hfm
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