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l NTRODUCTION TO MACHLNERY PRINCIPLES   25

                Notice that  as  the  magnetizing intensity  is  increased,  the  relative perme-
           ability first increases and then starts to drop off. The relative permeability of a typ-
           ical ferromagnetic  material as a function of the magnetizing intensity is shown in
           Figure  1-IOd. This shape is  fairly typical of all  ferromagnetic materials. It can
           easily be seen from the curve for ILr versus H that the assumption of constant rel-
           ative  permeability  made in Examples  1- 1 to  1-3 is  valid only over a  relatively
           narrow range of magnetizing intensities (or magnetomotive forces).
                In the  following  example.  the relative  permeability is  not  assumed to  be
           constant. Instead, the relationship between B and H is given by a graph.


                Example 1-5.  A square magnetic core has a mean path length of 55 cm and a cross-
                            2
           sectional area of 150 cm . A 200-turn coil of wire is wrapped around one leg of the core. The
           core is made of a material having the magnetization curve shown in Figure  l- lOc.
                (a)  How much current is required to produce 0.012 Wb of flux in the core?
                (b)  What is the core's relative permeability at that current level?
                (e)  What is its reluctance?

                Solution
                (a)  The required flu x density in the core is

                                 B = 1'.  =  1.012 Wb = 0.8 T
                                     A   0.015 01'
           From Figure  l- lOc,  the required magnetizing intensity is
                                    H =  11 5 A· turnslm
           From  Equation  (1- 20),  the  magnetomotivc  force  needed  to  produce  this  magnetizing
           intensity is
                          'if= Ni = H(
                            = (115 A -tums/m)(0.55 m) = 63.25 A -turns
           so the required current is
                               .  g   63.25 A • turns
                               t= N=  200 tums     0.3 16A
                (b)  The core's permeability at this current is

                                B      0.8T
                            }L  = Ii = 115 A .  turns/m   0.00696 Him
           Therefore, the relative permeability is

                                 = .l': =  0.00696 Him  = 5540
                               jJ.,   ""  4" X  10  7 Him
                (c)  The reluctance of the core is
                              'if   63.25 A • turns
                          'R = ¢ =   0.012 Wb   = 5270 A '  turnslWb
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