Page 319 - Electrical Properties of Materials
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Resonators and conditions of oscillation                   301

            12.4 Absorption and amplification
            Let us look now at energy levels 2 and 3 and consider the induced transition
            rate between them. It is

                                                 3
                                                c ρ(ν)
                              W 32 = B 32 ρ(ν)=  3  3   ,            (12.28)
                                             8πn hν t spont
            where eqns (12.11) and (12.13) have been used. The transition rate will of
            course depend on the lineshape function, so we need to multiply eqn (12.28)
                                                                  –2
            by g(ν). We shall also introduce the power density (measured in W m ) instead
                                             –3
            of the radiation density (measured in J m ) with the relation,
                                            c
                                        P d =  ρ,                    (12.29)
                                            n
            leading to the form,

                                           2
                                          c P d g(ν)
                                   W 32 =           .                (12.30)
                                               3
                                            2
                                        8πn hν t spont
               Now the number of induced transition per second is N 3 W 32 per unit volume,
            and the corresponding energy density per second is N 3 W 32 hν. For upward
            transitions, we obtain similarly N 2 W 32 hν, and hence the power lost in a dz
            thickness of the material is (N 3 – N 2 )W 32 hν dz. Denoting the change in power
            density across the dz element by dρ d , we obtain the differential equation,

                                                       2
                        dρ d                           c g(ν)
                            = γ (ν)ρ d ,  γ (ν)=(N 3 – N 2 )  ,      (12.31)
                                                       2 2
                         dz                         8πn ν t spont
            which has the solution,

                                  P d (Z)= P d (0) exp γ (ν)z.       (12.32)

               Under thermal equilibrium conditions N 3 < N 2 , and consequently, the input
            light suffers absorption. However, when N 3 > N 2 , that is there is a population
            inversion, the input light is amplified.


            12.5 Resonators and conditions of oscillation
            As we have said before, the energy levels are not infinitely narrow, hence emis-
            sion occurs in a finite frequency band. For single-frequency emission (by single
            frequency, we mean here a single narrow frequency range) all the excited states
            should decay in unison. But how would an atom in one corner of the mater-
            ial know when its mate in the other corner decides to take the plunge? They
            need some kind of coordinating agent or—in the parlance of the electronic
            engineer—a feedback mechanism. What could give the required feedback?
            The photons themselves. They stimulate the emission of further photons as
            discussed in the previous section and also ensure that the emissions occur
            at the right time. If we want to form a somewhat better physical picture of
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