Page 299 - Electromagnetics
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We find that when θ i <θ c the total field in region 1 behaves as a traveling wave
                        along x, but has characteristics of both a standing wave and a traveling wave along z
                        (Problem  4.7). The traveling-wave component is associated with a Poynting power flux,
                        while the standing-wave component is not. This flux is carried across the boundary
                        into region 2 where the transmitted field consists onlyof a traveling wave. By (4.161)
                        the normal component of time-average Poynting flux is continuous across the boundary,
                        demonstrating that the time-average power carried bythe wave into the interface from
                        region1 passes out through the interface into region2 (Problem  4.8).
                         Case 2: θ i <θ c .  The wave vectors are, from (4.289)–(4.290) and (4.296),

                                                    i
                                                   k = ˆ xβ 1 sin θ i + ˆ zβ 1 cos θ i ,
                                                    r
                                                   k = ˆ xβ 1 sin θ i − ˆ zβ 1 cos θ i ,
                                                    t
                                                   k = ˆ xβ 1 sin θ i − j ˆ zα c ,
                        where

                                                                2
                                                             2
                                                     α c =  β sin θ i − β 2 2
                                                            1
                        is the critical angle attenuation constant. The wave impedances are
                                                        η 1             β 2 η 2
                                                 Z 1⊥ =    ,    Z 2⊥ = j    ,
                                                       cos θ i          α c
                                                                        α c η 2
                                               Z 1  = η 1 cos θ i ,  Z 2  =− j  .
                                                                         β 2
                        Substituting these into (4.283) and (4.284), we find that the reflection coefficients are
                        the complex quantities

                                                ˜    β 2 η 2 cos θ i + jη 1 α c  jφ ⊥
                                                 ⊥ =                 = e   ,
                                                     β 2 η 2 cos θ i − jη 1 α c
                                               ˜     β 2 η 1 cos θ i + jη 2 α c  jφ
                                                   =−                 = e  ,
                                                     β 2 η 1 cos θ i − jη 2 α c
                        where

                                                  η 1 α c                        η 2 α c
                                   φ ⊥ = 2 tan −1         ,    φ   = π + 2 tan −1        .
                                               β 2 η 2 cos θ i                 β 2 η 1 cos θ i
                        We note with interest that ρ ⊥ = ρ   = 1. So the amplitudes of the reflected waves
                        are identical to those of the incident waves, and we call this the case of total internal
                        reflection. The phase of the reflected wave at the interface is changed from that of the
                        incident wave byan amount φ ⊥ or φ   . The phase shift incurred bythe reflected wave
                        upon total internal reflection is called the Goos–H¨anchen shift.
                          In the case of total internal reflection the field in region 1 is a pure standing wave while
                        the field in region 2 decays exponentially in the z-direction and is evanescent (Problem
                         4.9). Since a standing wave transports no power, there is no Poynting flux into region 2.
                        We find that the evanescent wave also carries no power and thus the boundarycondition
                        on power flux at the interface is satisfied (Problem 4.10 ). We note that for anyincident
                        angle except θ i = 0 (normal incidence) the wave in region 1 does transport power in the
                        x-direction.




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