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Figure A.5: Derivation of the Helmholtz transport theorem.


                        Using the notation

                                                           ∂      ∂      ∂
                                                  u ·∇ = u x  + u y  + u z
                                                          ∂x      ∂y    ∂z
                        we can write
                                                     DF    ∂F
                                                         =    + (u ·∇)F.                       (A.60)
                                                     Dt    ∂t
                        This is the material derivative of a vector field F when u describes the motion of a
                        physical material. Similarly, the total derivative of a vector field is
                                                      dF   ∂F
                                                         =    + (v ·∇)F
                                                      dt   ∂t
                        where v is arbitrary.

                        The Helmholtz and Reynolds transport theorems

                          We choose the intuitive approach taken by Tai [190] and Whitaker [214]. Consider
                        an open surface S(t) moving through space and possibly deforming as it moves. The
                        velocity of the points comprising the surface is given by the vector field v(r, t). We are
                        interested in computing the time derivative of the flux of a vector field F(r, t) through
                        S(t):
                                              d
                                       ψ(t) =       F(r, t) · dS
                                             dt  S(t)

                                                        F(r, t +  t) · dS −  F(r, t) · dS
                                                  S(t+ t)                S(t)
                                           = lim                                     .         (A.61)
                                              t→0                  t
                        Here S(t + t) = S 2  is found by extending each point on S(t) = S 1  through a displacement
                        v t, as shown in Figure A.5. Substituting the Taylor expansion

                                                                  ∂F(r, t)
                                             F(r, t +  t) = F(r, t) +    t +· · ·
                                                                    ∂t



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