Page 482 - Electromagnetics
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we see that A = ¯ a · B can be written as
                                                                          
                                                            a 11 a 12 a 13    B 1


                                             [A] = [¯ a][B] =   a 21 a 22 a 23     B 2    .


                                                            a 31 a 32 a 33    B 3


                          Note carefully that in (A.69) ¯ a operates on B from the left. A reorganization of the
                        components of ¯ a allows us to write
                                                     ¯ a = a 1 i 1 + a 2 i 2 + a 3 i 3         (A.71)
                                                          ˆ
                                                                ˆ
                                                                      ˆ
                        where
                                                                         ˆ
                                                                  ˆ
                                                           ˆ
                                                  a 1 = a 11 i 1 + a 21 i 2 + a 31 i 3 ,
                                                           ˆ
                                                                  ˆ
                                                                         ˆ
                                                  a 2 = a 12 i 1 + a 22 i 2 + a 32 i 3 ,
                                                                         ˆ
                                                           ˆ
                                                                  ˆ
                                                  a 3 = a 13 i 1 + a 23 i 2 + a 33 i 3 .
                                                                                  ˆ
                                                                                        ˆ
                                                                            ˆ
                        We may now consider using ¯ a to operate on a vector C = i 1 C 1 + i 2 C 2 + i 3 C 3 from the
                        right:
                                            C · ¯ a = (C · a 1 )i 1 + (C · a 2 )i 2 + (C · a 3 )i 3 .
                                                         ˆ
                                                                   ˆ
                                                                              ˆ
                        In matrix form C · ¯ a is
                                                                        

                                                           a 11 a 21 a 31    C 1

                                                  T
                                                [¯ a] [C] =   a 12 a 22 a 32     C 2  


                                                           a 13 a 23 a 33    C 3


                        where the superscript “T ” denotes the matrix transpose operation. That is,
                                                                T
                                                        C · ¯ a = ¯ a · C
                               T
                        where ¯ a is the transpose of ¯ a.
                          If the primed and unprimed frames coincide, then
                                                     ˆ ˆ       ˆ ˆ      ˆ ˆ
                                               ¯ a = a 11 (i 1 i 1 ) + a 12 (i 1 i 2 ) + a 13 (i 1 i 3 ) +
                                                     ˆ ˆ       ˆ ˆ      ˆ ˆ
                                                + a 21 (i 2 i 1 ) + a 22 (i 2 i 2 ) + a 23 (i 2 i 3 ) +
                                                               ˆ ˆ
                                                                        ˆ ˆ
                                                     ˆ ˆ
                                                + a 31 (i 3 i 1 ) + a 32 (i 3 i 2 ) + a 33 (i 3 i 3 ).
                        In this case we may compare the results of ¯ a · B and B · ¯ a for a given vector B =
                        ˆ i 1 B 1 + i 2 B 2 + i 3 B 3 . We leave it to the reader to verify that in general
                                    ˆ
                              ˆ
                                                         B · ¯ a  = ¯ a · B.
                        Vector form representation.  We can express dyadics in coordinate-free fashion if we
                        expand the concept of a dyad to permit entities such as AB. Here A and B are called
                        the antecedent and consequent, respectively. The operation rules
                                          (AB) · C = A(B · C),  C · (AB) = (C · A)B,
                        define the anterior and posterior products of AB with a vector C, and give results
                        consistent with our prior component notation. Sums of dyads such as AB + CD are
                        called dyadic polynomials, or dyadics. The simple dyadic
                                                        ˆ
                                                  ˆ
                                                              ˆ
                                         AB = (A 1 i 1 + A 2 i 2 + A 3 i 3 )(B 1 i 1 + B 2 i 2 + B 3 i 3 )
                                                                     ˆ
                                                                                  ˆ
                                                                           ˆ
                        © 2001 by CRC Press LLC
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