Page 138 -
P. 138

F(x) is then called an iteration function, and it can be used for the generation
                             of the sequence:

                                                          x  = F(x )                        (5.2)
                                                                  k
                                                           k+1
                              To guarantee that this method gives accurate results in a specific case, the
                             function should be continuous and it should satisfy the contraction condition:


                                                    Fx(  ) −  Fx(  ) ≤  s x −  x            (5.3)
                                                       n     m      n   m

                             where 0 ≤ s < 1; that is, the changes in the value of the function are smaller
                             than the changes in the value of the arguments. To prove that under these
                             conditions, the iterative function possesses a fixed point (i.e., that ultimately
                             the difference between two successive iterations can be arbitrarily small) that
                             can be immediately obtained from the above contraction condition [Eq. (5.3)].
                             PROOF Let the x guess  be the first term in the iteration, then:

                                                  Fx() −  Fx(  ) ≤ s x −  x                 (5.4)
                                                     1      guess   1  guess

                             but since


                                                 Fx(   ) =  x  and  F x( ) =  x             (5.5)
                                                    guess  1          1    2
                             then


                                                      x −  x ≤ s x −  x                     (5.6)
                                                       2   1    1   guess

                             Similarly,

                                                    Fx() −  Fx( ) ≤  s x −  x               (5.7)
                                                       2      1     2  1

                             translates into


                                                 x − x ≤ s x − x ≤  s x −  x                (5.8)
                                                                   2
                                                  3   2    2   1     1   guess
                             The argument can be extended to the (m + 1)-iteration, where we can assert
                             that:


                                                               m
                                                    x   − x ≤  s x −  x                     (5.9)
                                                     m+1   m      1  guess
                             © 2001 by CRC Press LLC
   133   134   135   136   137   138   139   140   141   142   143