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x(k)=(b(k)-U(k,k+1:n)*x(k+1:n))/U(k,k);
                                   end
                                x





                             8.7  Application of Matrix Methods

                             This section provides seven representative applications that illustrate the
                             immense power that matrix formulation and tools can provide to diverse
                             problems of common interest in electrical engineering.


                             8.7.1  dc Circuit Analysis

                             Example 8.6
                             Find the voltages and currents for the circuit given in Figure 8.1.


                                                    50 Ω                    100 Ω
                                      V 1                         V 2                  V 3
                                                            I 1      I 2
                                                                     I 3
                                         5 V              300 Ω                Lamp
                                                                                 R L






                              FIGURE 8.1
                              Circuit of Example 8.6.

                             Solution: Using Kirchoff’s current and voltage laws and Ohm’s law, we can
                             write the following equations for the voltages and currents in the circuit,
                             assuming that R  = 2Ω:
                                           L
                                                        V =  5
                                                         1
                                                        V − V =  50 I
                                                         1   2     1
                                                        V − V =  100 I
                                                         2   3      2
                                                        V =  300 I
                                                         2      3
                                                        V =  I 2
                                                         3    2
                                                        I =  I +  I
                                                         1  2   3


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