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August 18, 2010 11:36      9in x 6in     b985-ch06     Elementary Physical Chemistry





                               54                   Elementary Physical Chemistry

                               and


                                             Π= −RT/V ln x A ≈−RT/[V ln(1 − x B )]
                                               = x B RT/V ≈ n B /[(n A + n B )(RT/V m )]

                                               =(n B /V )RT ≈ [B]RT                       (6.19)




                               6.2.6. Chemical Reaction Equilibria

                               The relation between K and ∆G  o  was already discussed in previous
                               chapters. Here, we will make a few remarks which were not sufficiently
                               emphasized before.

                               a) From the free energy or chemical potentials, we can derive for the
                                 reaction


                                                    aA + bB ··· =cC + dD ···              (6.20)

                                 producing the quilibrium constant

                                                            c
                                                               d
                                                                     a
                                                       K = a a .../a a b                  (6.21)
                                                                     A B
                                                            C D
                                 where the activities are related to partial pressures or to concentrations,
                                 etc. The expression of K in terms of the activities is exact, but the
                                 relation of the activities to pressure, to concentration, as shown in
                                 Eqs. (5.22a–c), are approximate. Activities are equal to the mole fraction
                                 times activity coefficients, which are not easily calculated.
                              b) Consider the heterogeneous reaction,

                                                   CaCO 3(s) = CaO(s) + CO 2(g)           (6.22)


                                 It is found that K depends only on the partial pressure P(CO 2)of
                                 the gas, i.e. K = P(CO 2 ) and not on the other substances. Reason:
                                 the activity of each solid is 1, and the activity of the gas is to a good
                                 approximation equal to the partial pressure.
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