Page 70 - Bruno Linder Elementary Physical Chemistry
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August 18, 2010 11:36      9in x 6in     b985-ch06     Elementary Physical Chemistry





                                                Phase and Chemical Equilibria              55

                            c) Also, consider the equilibrium constant for the reaction


                                                            +
                                                                      −
                                              2H 2 O(l) = H 3 O (aq) + OH (aq)         (6.23)
                              A neutral system in equilibrium has

                                                    +
                                               [H 3 O ]= [OH ]= 10 −7  mol/L           (6.24)
                                                            −

                              The activity of the pure liquid is essentially constant, yielding an
                              equilibrium constant, denoted as K w ,equal to


                                                        K w =10 −14                    (6.25)


                            Example 6.4. The standard enthalpies of formation of C 6 H 5 COOH(s),
                            CO 2 (g) and H 2 O(l) are respectively −386.0 kJ, −285.8kJ and −393.5kJ.
                            Calculate

                                                       o
                            (a) the standard enthalpy, ∆H comb ,and
                            (b) the standard energy, ∆U o  ,
                                                     comb

                            of combustion of [C 6 H 5 COOH(s)].

                            The combustion reaction is

                                                      15
                                      C 6 H 5 COOH(s) +  O 2 (g) → 7CO 2 (g) + 3H 2 O(l)
                                                      2

                            and so

                                                                           o
                                                             o
                                             o
                            (a) ∆H o   =7∆H [CO 2 (g)] + 3∆H [H 2 O(l)] − ∆H [C 6 H 5 COOH(s)]
                                   comb      f               f             f
                                       =7(−285.8) + 3(−393.5) − (−386.0) = −2795.1kJ
                                  o         o
                            (b) ∆U     =∆H      − ∆(PV )
                                  comb      comb
                                ∆(PV )= 7PV m [CO 2 (g)] + 3PV m [H 2 O(l)] − PV m [C 6 H 5 COOH(s)]
                                          15
                                        −   PV m [O 2(g)]
                                           2
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