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                                                7.4 Sums of Random Variables                 213

                        It follows that the characteristic function of X = (X 1 ,..., X n )is
                                                                n

                                                 ϕ X (t 1 ,..., t n ) =  ϕ(t i ).
                                                               j=1
                                                              n
                          Hence, the characteristic function of S =  X j is given by
                                                              j=1
                                                                 λ n
                                                           n
                                                 ϕ S (t) = ϕ(t) =     .
                                                               (λ − it) n
                        This is the characteristic function of the gamma distribution with parameters n and λ; see
                        Example 3.4. It follows that S has a gamma distribution with parameters n and λ.

                          The techniques described in the previous section can be used to find the density or
                        frequency function of a sum.

                        Theorem 7.5. Let X = (X 1 ,..., X n ) where X 1 ,..., X n denotes a sequence of real-valued
                                               n

                        random variables, let S =  X j and let S denote the range of S.
                                                j=1
                           (i) Suppose X has a discrete distribution with frequency function p. Then S has a
                              discrete distribution with frequency function p S where

                                            p S (s) =            p(x 1 ,..., x n ), s ∈ S
                                                           n
                                                   {(x 1 ,...,x n ):  j=1 x j =s}
                          (ii) Suppose X has an absolutely continuous distribution with density function p. Then
                              S has an absolutely continuous distribution with density function p S where

                                            ∞      ∞
                                                            n

                                   p S (s) =  ···    p s −    x j , x 2 ,..., x n  dx 2 ··· dx n , s ∈ R
                                           −∞     −∞        j=2
                        Proof. Let f denote a bounded, real-valued function defined on S, the range of S. Then,
                        if X has discrete distribution with frequency function f ,

                           E[ f (S)] =      f (s)p(x 1 ,..., x n ) =           f (s)p(x 1 ,..., x n )
                                                                         n
                                    (x 1 ,...,x n )∈X        s∈S {(x 1 ,...,x n ):
                                                                        j=1 x j =s}

                                  =    f (s)              p(x 1 ,..., x n );
                                                    n
                                    s∈S    {(x 1 ,...,x n ):  j=1 x j =s}
                        part (i) of the theorem follows.
                          Now suppose that X has an absolutely continuous distribution with density function p.
                        To prove part (ii), we can use Theorem 7.2 with the function
                                                                      n

                                             g(x) = (s, x 2 ,..., x n ), s =  x j .
                                                                     j=1
                        Then Y = g(X) has density
                                              p(y 1 − (y 2 +· · · + y n ), y 2 ,..., y n );

                        note that the Jacobian here is equal to 1. Hence, the marginal density of Y 1 = S is
                                      ∞      ∞

                                        ···    p(y 1 − (y 2 +· · · + y n )y 2 ,..., y n ) dy 2 ··· dy n ;
                                     −∞     −∞
                        rewriting this in terms of s = y 1 and x j = y j , j = 2,..., n, proves the result.
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